只专门化(一部分)模板类的一个方法 [英] specialize only (a part of) one method of a template class

问题描述

如果我有一个模板类

template<typename T>
class C {
public:
    void method1() { ... }
    void method2() { ... }
    std::string method3(T &t) {
        // ...
        std::string s = t.SerializeToString();
        // ...
        return s;
    }
    // ...
};

并且我想将它专门用于 T = std::string 但只更改 method3(T&)(保留所有其他方法)，或者甚至更好，仅更改method3 的那部分，对于 T = std::string 将简单地变成 std::string s = t;，对当前代码的影响最小(方法重复较少)签名，更少的子类化)，我该怎么做?

and I want to specialize it for T = std::string but only changing method3(T&) (keeping all other methods), or even better, only that part of method3, which for T = std::string would simply become std::string s = t;, with minimum impact on current code (less repetition of methods signatures, less subclassing), how would I do it?

我正在 C++11 中开发

I'm developing in C++11

推荐答案

你可以像这样使用特化(不需要特化整个类):

You can use specialization like that (no need to specialize the whole class):

template<>
std::string C<string>::method3(string &t) {
    // ...
    std::string s = t;
    // ...
    return s;
}

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