使用 tidyr::separate 和 sep="" 将一列分成多列 [英] Separate a column into multiple columns using tidyr::separate with sep=""

问题描述

df <- data.frame(category = c("X", "Y"), sequence = c("AAT.G", "CCG-T"), stringsAsFactors = FALSE)

df
 category sequence
1        X     AAT.G
2        Y     CCG-T

我想将 sequence 列分成 5 列(每个字符一列).我试图用 tidyr::separate 做到这一点，但它在内部使用 stringi::stri_split_regex 它不接受空字符串作为分隔符(尽管 sep 参数应采用正则表达式).

I want to separate the column sequence into 5 columns (one for each character). I tried to do that with tidyr::separate but it internally uses stringi::stri_split_regex which doesn't accept an empty string as a separator (although the sep argument should take a regex).

library(tidyr)
separate(df, sequence, into = paste0("V", 1:5), sep="")

Error: Values not split into 5 pieces at 1, 2
In addition: Warning messages:
1: In stringi::stri_split_regex(value, sep, n_max) :
  empty search patterns are not supported
2: In stringi::stri_split_regex(value, sep, n_max) :
  empty search patterns are not supported

预期输出如下:

  category V1 V2 V3 V4 V5
1        X  A  A  T  .  G
2        Y  C  C  G  -  T

推荐答案

你可以用 extract from tidyr

You could do this with extract from tidyr

library(tidyr)
extract(df, sequence, into=paste0('V', 1:5), '(.)(.)(.)(.)(.)')
#  category V1 V2 V3 V4 V5
#1        X  A  A  T  .  G
#2        Y  C  C  G  -  T

或者用 gsub 创建一个分隔符，并将其用作 sep 作为 separator

Or create a delimiter with gsub and use that as sep for the separator

library(dplyr)
library(tidyr)
df %>% 
   mutate(sequence=gsub('(?<=.)(?=.)', ',', sequence, perl=TRUE)) %>% 
   separate(sequence, into=paste0('V', 1:5), sep=",")
#  category V1 V2 V3 V4 V5
#1        X  A  A  T  .  G
#2        Y  C  C  G  -  T

或者你可以使用cSplit

library(splitstackshape)
setnames(cSplit(df, 'sequence', '', stripWhite=FALSE),
             2:6, paste0('V', 1:5))[]
#   category V1 V2 V3 V4 V5
#1:        X  A  A  T  .  G
#2:        Y  C  C  G  -  T

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