如何用 map 替换这个 for 循环以获得 data.frames 列表? [英] How do I replace this for-loop with map for a list of data.frames?
问题描述
我有一个 data.frames
的 list
,我想使用 as.numeric()<将其转换为
binary
变量/代码>.
I have a list
of data.frames
that I want to convert into binary
variables using as.numeric()
.
我正在寻找替换这个脚本,
I am looking to replace this script,
data_list <- list(
mtcars,
diamonds
)
for (i in 1:length(data_list)) {
# extract data;
temp_data <- data_list[[i]]
# extract lenght;
col_length <- ncol(temp_data)
for (j in 1:col_length) {
# Only do the operation if it is a numeric/double
# class variable
if (inherits(temp_data[,j], c("numeric", "double"))) {
temp_data[,j] <- as.numeric(
temp_data[,j] > 1
)
} else {
next()
}
}
# Store it back to the list
data_list[[i]] = temp_data
}
具有 tidyverse
- 和 map
- 类型的解决方案.
with a tidyverse
- and map
-type of solution.
推荐答案
您可以使用 mutate
和 across
并添加 selection helper
where()
对您想要的 class
变量进行操作.
You can use mutate
with across
and add the selection helper
where()
to do your operation on your desired class
of variables.
data_list <- list(
mtcars,
iris
)
data_list <- data_list %>% map(
~ .x %>% mutate(
across(where(is.numeric), ~ as.numeric(. > 1))
)
)
across(where(is.numeric), ~ as.numeric(. > 1))
查找所有 numeric
变量 across您的 data.frame
并将它们单独转换为 binary
变量.
The across(where(is.numeric), ~ as.numeric(. > 1))
finds all numeric
variables across your data.frame
and converts them individually to binary
variables.
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