倾斜表面辐射的solar时间戳 [英] solaR timestamp for radiation on a tilted surface
问题描述
我正在尝试使用 R 包 solaR 来计算倾斜平面上的辐照度给定在水平面上测量的辐照度.我可以让代码工作，但最终的输出时间戳没有意义.
可以在.
另外，你应该看看help(timezone)的信息和例子.
I am trying to use the R package solaR to calculate irradiance on a tilted plane given measured irradiance on the horizontal plane. I can get the code to work, but the final output timestamp does not make sense.
Data for this code can be found here. It is one day's worth of measured irradiance (global horizontal -- ghz, direct normal -- dir, diffuse horizontal -- dhz, and outdoor temp ta) for Austin, TX. The timestamp is local 'CST6CDT' time. The data is for a clear day, so that maximum value of global horizontal (ghz) should roughly correspond with solar noon (the time that the sun crosses the local meridian).
My code is as follows:
library(solaR)
sol_data <- read.csv(file)
# The data must be named a certain way.
names(sol_data) <- c('time', 'G0', 'B', 'D0', 'Ta')
# The negatives are an artifact of the sensor and are set to 0.
sol_data$G0 <- ifelse(sol_data$G0 < 0, 0, sol_data$G0)
sol_data$B <- ifelse(sol_data$B < 0, 0, sol_data$B)
sol_data$D0 <- ifelse(sol_data$D0 < 0, 0, sol_data$D0)
# This calculates the beam incidence on the horizontal plane.
sol_data$B0 <- sol_data$G0 - sol_data$D0
sol_data$B0 <- ifelse(sol_data$B0 < 0, 0, sol_data$B0)
# This takes the data and assigns the timestamp to a certain format and timezone
idxLocal <- with(sol_data, as.POSIXct(time, format='%Y-%m-%d %H:%M:%S', tz = 'CST6CDT'))
# This converts the timestamp to solar time
idx <- local2Solar(idxLocal, lon = -97.7428)
# Creates a zoo object needed to make the Meteo file for input
z <- zoo(sol_data[,c('G0', 'D0', 'B0', 'Ta')], idx)
# local latitude
lat = 30.2669
# Creates a Meteo file
My_Meteo <- zoo2Meteo(z, lat=lat)
# Finds the start and end date of the input file
start <- idx[1]
end <- idx[length(idx)]
# Returns a base time for the calculations
BTd <- fBTd(mode = 'serie', year = '2013', start = start, end = end, format = '%Y-%m-%d %H:%M:%S')
# Computes the movement of the sun/earth
sol <- calcSol(lat = 30.2669, BTd, sample = 'min')
# Creates a G0 file for solar rad on horizontal surface
compI <- calcG0(30.2669, modeRad = 'bdI', dataRad = My_Meteo, corr = 'none')
# creates the angles for calculation of the rad on a tilted surface
angGen <- fTheta(sol = sol, beta = 0, alfa = 0)
# Calculates the irradiance on a tilted surface
irad_tilt <- fInclin(compI, angGen)
When I use beta = 0, alfa = 0 (a flat plane) I should get roughly the same output as my input. However, when I search for the max value of global horizontal irradiance:
x <- which.max(irad_tilt$G)
irad_tilt[x,]
I get it to return a max at 2013-05-05 10:43:01 and I cannot figure out what/why this time is as it is. It is not local time, that should be around 13:24. Local solar time should be around 12:00. UTC time should be around 18:24, and UTC solar time (if there is such a thing) should be 17:00...
I know this is obscure, but any thoughts?
I have tested the code and data in my computer with correct results. Let's reproduce the main steps with some graphical outputs:
library(solaR)
sol_data <- read.csv('/tmp/one_day_WSL_8.csv')
## The data must be named a certain way.
names(sol_data) <- c('time', 'G0', 'B', 'D0', 'Ta')
## The negatives are an artifact of the sensor and are set to 0.
sol_data$G0 <- ifelse(sol_data$G0 < 0, 0, sol_data$G0)
sol_data$B <- ifelse(sol_data$B < 0, 0, sol_data$B)
sol_data$D0 <- ifelse(sol_data$D0 < 0, 0, sol_data$D0)
## This calculates the beam incidence on the horizontal plane.
sol_data$B0 <- sol_data$G0 - sol_data$D0
sol_data$B0 <- ifelse(sol_data$B0 < 0, 0, sol_data$B0)
## This takes the data and assigns the timestamp to a certain format and timezone
idxLocal <- with(sol_data, as.POSIXct(time, format='%Y-%m-%d %H:%M:%S', tz = 'CST6CDT'))
The function local2Solar converts the time zone of a POSIXct object to the mean solar time and set its time zone to UTC as a synonym of mean solar time. It includes two corrections: the difference of longitudes between the location and the time zone, and the daylight saving time.
idx <- local2Solar(idxLocal, lon = -97.7428)
## Creates a zoo object needed to make the Meteo file for input
z <- zoo(sol_data[,c('G0', 'D0', 'B0', 'Ta')], idx)
Because your data belongs to a clear day and this time series uses mean solar time, the maximum should be located around noon.
xyplot(z, type=c('l', 'g'))
Now we compute the sun geometry with calcSol. Here I am using a
different code from yours.
## local latitude
lat = 30.2669
## Computes the movement of the sun/earth
sol <- calcSol(lat, BTi=idx)
xyplot(as.zooI(sol), type=c('l', 'g'))
Next we calculate radiation on the horizontal surface.
g0 <- calcG0(lat, modeRad = 'bdI', dataRad = z, corr = 'none')
xyplot(as.zooI(g0), type=c('l', 'g'))
Finally, with calcGef we obtain irradiance on a tilted surface:
gef <- calcGef(lat=lat, modeRad='bdI', dataRad=z)
xyplot(as.zooI(gef), type=c('l', 'g'))
I suspect that your problem is related with time zones defined in your computer. Could you check these results?:
lonHH('America/Chicago')
## [1] -1.570796
lonHH('CDT6CST')
## [1] -1.570796
idxLocal1 <- as.POSIXct(sol_data$time, format='%Y-%m-%d %H:%M:%S', tz = 'CST6CDT')
idxLocal2 <- as.POSIXct(sol_data$time, format='%Y-%m-%d %H:%M:%S', tz = 'America/Chicago')
idxUTC1 <- as.POSIXct(format(idxLocal1, tz='UTC'), tz='UTC')
idxUTC2 <- as.POSIXct(format(idxLocal2, tz='UTC'), tz='UTC')
all.equal(idxUTC1, idxUTC2)
## [1] TRUE
Maybe these technical notes are useful for additional information on this topic:
- Ripley, B. D. and Hornik, K. (2001) Date-time classes. R News, 1/2, 8–11.
- Gabor Grothendieck and Thomas Petzoldt (2004), Date and Time Classes in R, R News 4(1), 29-32.
Besides, you should take a look at the information and examples of help(timezone).
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