Unix时间戳为FAT时间戳 [英] Unix timestamp to FAT timestamp

问题描述

我试着去一时间结构转换为FAT时间戳。我的code如下：

 无符号长脂肪（tm_struct PTIME）
{
    无符号长FatTime = 0;    FatTime | =（pTime.seconds / 2）GT;＆GT; 1;
    FatTime | =（pTime.minutes）LT;＆LT; 5;
    FatTime | =（pTime.hours）LT;＆LT; 11;
    FatTime | =（pTime.days）LT;＆LT; 16;
    FatTime | =（pTime.months）LT;＆LT; 21;
    FatTime | =（pTime.years +20）＆所述;＆下; 25;    返回FatTime;
}
 

是否有人有正确的code？

解决方案

 的DOS日期/时间格式是位掩码：               24 16 8 0
+  -  +  -  +  -  +  -  +  -  +  -  +  -  +  -  +  -  +  -  +  -  +  -  +  -  +  -  +  -  +  -  + +  -  +  -  +  -  +  -  +  -  +  -  +  -  +  - +  -  +  -  +  -  +  -  +  -  +  -  +  -  +  -  +
| Y | Y | Y | Y | Y | Y | Y | M | | M | M | M | D | D | D | D | D | | H | H | H | H | H | M | M | M | | M | M | M | S | S | S | S | S |
+  -  +  -  +  -  +  -  +  -  +  -  +  -  +  -  +  -  +  -  +  -  +  -  +  -  +  -  +  -  +  -  + +  -  +  -  +  -  +  -  +  -  +  -  +  -  +  - +  -  +  -  +  -  +  -  +  -  +  -  +  -  +  -  +
 \\ ___________ / \\ ________ / \\ _________ / \\ ________ / \\ ____________ / \\ _________ /
    年月日时分秒年存储为1980偏移。
秒存储在两秒钟的增量。
（因此，如果第二值是15，它实际上重新presents 30秒。）
 

我不知道你使用的是tm_struct但如果它是 http://www.cplusplus.com/reference/ctime / TM / 然后

 无符号长FatTime =（（pTime.tm_year  -  80）＆LT;＆LT; 25）|
                        （pTime.tm_mon＆LT;＆LT; 21）|
                        （pTime.tm_mday＆LT;＆LT; 16）|
                        （pTime.tm_hour＆所述;＆下; 11）|
                        （pTime.tm_min＆所述;小于5）|
                        （pTime.tm_sec＆GT;大于1）;
 

Im trying to convert a time structure to a FAT timestamp. My code looks like:

unsigned long Fat(tm_struct pTime)
{
    unsigned long FatTime = 0;

    FatTime |= (pTime.seconds / 2) >> 1;
    FatTime |= (pTime.minutes) << 5;
    FatTime |= (pTime.hours) << 11;
    FatTime |= (pTime.days) << 16;
    FatTime |= (pTime.months) << 21;
    FatTime |= (pTime.years + 20) << 25;

    return FatTime;
}

Does someone have the correct code?

解决方案

The DOS date/time format is a bitmask:

               24                16                 8                 0
+-+-+-+-+-+-+-+-+ +-+-+-+-+-+-+-+-+ +-+-+-+-+-+-+-+-+ +-+-+-+-+-+-+-+-+
|Y|Y|Y|Y|Y|Y|Y|M| |M|M|M|D|D|D|D|D| |h|h|h|h|h|m|m|m| |m|m|m|s|s|s|s|s|
+-+-+-+-+-+-+-+-+ +-+-+-+-+-+-+-+-+ +-+-+-+-+-+-+-+-+ +-+-+-+-+-+-+-+-+
 \___________/\________/\_________/ \________/\____________/\_________/
    year        month       day      hour       minute        second

The year is stored as an offset from 1980. 
Seconds are stored in two-second increments. 
(So if the "second" value is 15, it actually represents 30 seconds.)

I dont know the tm_struct you are using but if it's http://www.cplusplus.com/reference/ctime/tm/ then

unsigned long FatTime = ((pTime.tm_year - 80) << 25) | 
                        (pTime.tm_mon << 21) |
                        (pTime.tm_mday << 16) |
                        (pTime.tm_hour << 11) |
                        (pTime.tm_min << 5) |
                        (pTime.tm_sec >> 1);

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