datetime到Unix时间戳，精度为毫秒 [英] datetime to Unix timestamp with millisecond precision

问题描述

我正在尝试做一些非常简单的事情，将一个 datetime 对象在未来三天转换为Unix UTC时间戳记：

I'm trying to do something really simple, convert a datetime object three days into the future into a Unix UTC timestamp:

import datetime, time
then = datetime.datetime.now() + datetime.timedelta(days=3)
# Method 1
print then.strftime("%s")
# Method 2
print time.mktime(then.timetuple())
# Method 3 
print time.mktime(then.timetuple()) * 1000

方法1和2给我的Unix时间在秒，而不是毫秒，方法3给出毫秒，毫秒毫秒毫秒。

Method 1 and 2 give me Unix time in seconds, not milliseconds, and method 3 gives me milliseconds with no actual millisecond precision.

当我打印然后时，我得到 datetime.datetime（2011， 19，15，16，8，278271），所以我知道精度可用于毫秒。如何获取实际毫秒精度的Unix时间戳？如果它作为一个浮点数返回，我必须将它压缩到一个 int ，没关系。有没有解决方案我在寻找这样做？

When I simply print then, I get datetime.datetime(2011, 11, 19, 15, 16, 8, 278271), so I know that the precision is available for milliseconds. How can I get a Unix timestamp with actual millisecond precision? If it's returned as a float and I have to flatten it to an an int, that's fine. Is there a solution I'm looking for that does this?

推荐答案

日期时间对象有一个名为 microsecond 的字段。所以实现你所需要的一种方法是：

Datetime objects have a field named microsecond. So one way to achieve what you need is:

time.mktime(then.timetuple())*1e3 + then.microsecond/1e3

从UNIX时代起，以所需精度返回毫秒。

This returns milliseconds since UNIX epoch with the required precision.

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