批次：时间戳UNIX时间 [英] Batch: Timestamp to UNIX Time

问题描述

据我所知，批不具有使UNIX时间的命令。最近一个我能找到的是％TIME％，只显示时间戳。

For all I know, Batch does not have a command that gives the UNIX time. The closest one I can find is %time%, which only displays the timestamp.

是否有一个命令，或设置批处理命令，使用它可以得到UNIX时间的？

Is there a command, or set of commands in Batch with which you can get the UNIX time?

推荐答案

有的里奇劳伦斯的批量库具有所有这些漂亮好用的脚本。你需要的是<一个href=\"http://www.commandline.co.uk/lib/treeview/index.php?contents.php&../Batch%20Function%20Library/Date%20and%20Time%20Functions/DateToSecs.html\">DateToSec （使用<一个href=\"http://www.commandline.co.uk/lib/treeview/index.php?contents.php&../Batch%20Function%20Library/Date%20and%20Time%20Functions/GetDate.html\">GetDate和<一个href=\"http://www.commandline.co.uk/lib/treeview/index.php?contents.php&../Batch%20Function%20Library/Date%20and%20Time%20Functions/GetTime.html\">GetTime).

There's Richie Lawrence's batch library that has all those nifty handy scripts. The one you need is DateToSec (which uses GetDate and GetTime).

下面是一个简单的脚本，它采用一个小<一href=\"http://msdn.microsoft.com/en-us/library/windows/desktop/aa394582%28v=vs.85%29.aspx\">WMI:

Here's a simplified script, that employs a little WMI:

@echo off
setlocal
call :GetUnixTime UNIX_TIME
echo %UNIX_TIME% seconds have elapsed since 1970-01-01 00:00:00
goto :EOF

:GetUnixTime
setlocal enableextensions
for /f %%x in ('wmic path win32_utctime get /format:list ^| findstr "="') do (
    set %%x)
set /a z=(14-100%Month%%%100)/12, y=10000%Year%%%10000-z
set /a ut=y*365+y/4-y/100+y/400+(153*(100%Month%%%100+12*z-3)+2)/5+Day-719469
set /a ut=ut*86400+100%Hour%%%100*3600+100%Minute%%%100*60+100%Second%%%100
endlocal & set "%1=%ut%" & goto :EOF

结果将返回到传递到 GetUnixTime 第一个参数，即％UNIX_TIME％。

例如：

The result will be returned into the first parameter passed to GetUnixTime, i.e. %UNIX_TIME%.
For example:

1341791426 seconds have elapsed since 1970-01-01 00:00:00

希望它帮助！

这篇关于批次：时间戳UNIX时间的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！