使用纬度和经度转换为本地时区? [英] convert to local time zone using latitude and longitude?

问题描述

我有一个包含以下信息的数据集:纬度、经度、EST 时间.例如，对于一个观察

I have a data set with the following information: latitude, longitude, EST time. For example, for one observation

lat = 13
long = -2
time1 = as.POSIXlt("2014-02-12 17:00:00", tz = "EST")

我想创建一个新的变量 timeL，即本地时间.有关如何使用 R 执行此操作的任何建议?

I want to create a new variable timeL that is the local time. Any suggestions of how to do this with R?

谢谢！

推荐答案

lat = 13
long = -2
time1 <- as.POSIXct("2014-02-12 17:00:00", tz = "EST")
# https://developers.google.com/maps/documentation/timezone/
apiurl <- sprintf("https://maps.googleapis.com/maps/api/timezone/%s?location=%s,%s&timestamp=%d&sensor=%s", 
                  "xml", 
                  lat, 
                  long, 
                  as.numeric(time1), 
                  "false")
library(XML)
tz <- xmlParse(readLines(apiurl))[["string(//time_zone_id)"]]
as.POSIXct(format(time1, tz=tz))
# [1] "2014-02-12 22:00:00 CET"

或者，按照@SymbolixAU 的建议，使用他们的 googleway 包:

or, as suggested by @SymbolixAU, use their googleway package:

res <- googleway::google_timezone(c(lat, long), time1, key = NULL)
as.POSIXct(format(time1, tz=res$timeZoneId))
# [1] "2014-02-12 22:00:00 CET"

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