Python Tkinter 按钮回调 [英] Python Tkinter button callback

问题描述

当我单击由 for 循环创建的每个按钮时，我试图打印出按钮编号.以下是我尝试过的.

I am trying to print out the button number when i click each buttons that are created by for loop. The following is what i have tried.

import Tkinter as tk
root=tk.Tk()

def myfunction(a):
        print a

for i in range(10):
    tk.Button(root,text='button'+str(i),command=lambda:myfunction(i)).place(x=10,y=(10+(25*i)))
root.mainloop()

但它不是打印出每个按钮编号，而是每次都给我最后一个按钮编号.有什么我可以做的，以便当我单击按钮 1 时，它会为 2 打印 1,2，依此类推?

But instead of printing out each button number, it actually giving me the last button number everytime. Is there anything i can do so that when i click button 1, it will print 1,2 for 2 ,and so on?

推荐答案

Blender 的答案是一个聪明的解决方案，但如果您被函数抽象所困扰，这里是另一种可能的方法.它实际上只是创建了一个映射，保存在 buttons 中，从 Button 小部件到其正确的数字.

Blender's answer is a clever solution but in case you get thrown off by the function abstraction, here is another possible way to do it. It really just creates a mapping, saved in buttons, from Button widgets to their proper numbers.

import Tkinter as tk
root = tk.Tk()

def myfunction(event):
    print buttons[event.widget]

buttons = {}
for i in range(10):
    b = tk.Button(root, text='button' + str(i))
    buttons[b] = i # save button, index as key-value pair
    b.bind("<Button-1>", myfunction)
    b.place(x=10,y=(10+(25*i)))
root.mainloop()

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