转换维数组到一个二维数组的元素计数 [英] Converting 1D array to a 2D array with count of elements
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问题描述
我卡住了,我想知道,如果有人能在正确的方向指向我。
I'm stuck and am wondering if someone could point me in the right direction.
我有一个包含数字的数组,例如:
I have an array containing numbers, eg:
$start = array(0,0,0,45,45,0,3,0,0,1,1,1,1);
和希望该数组转换为数组:
And would like that array to convert to this array:
$result = array( array('id'=>0, 'aantal'=>3,
array('id'=>45,'aantal'=>2),
array('id'=>0, 'aantal'=>1),
array('id'=>3,'aantal'=>1),
array('id'=>0, 'aantal'=>1),
array('id'=>1,'aantal'=>4)
)
我试过遍历$启动阵列,但我被困旁观起来$开始第n-1,而无需关键。
I tried traversing the $start array, but I got stuck onlooking up the n-1 in $start without having the key.
有没有人对我怎么能做到这一点有什么建议?
Does anyone have any advice on how I can do this?
推荐答案
这将是游程编码项目的数组典型的方法:
This would be the typical approach for run length encoding an array of items:
$array = array(0,0,0,45,45,0,3,0,0,1,1,1,1);
$last = null;
$current = null;
$result = array();
foreach ($array as $item) {
if ($item == $last) {
// increase frequency by 1
++$current['aantal'];
} else {
// the first iteration will not have a buffer yet
if ($current) {
$result[] = $current;
}
// create buffer array item, set frequency to 1
$current = array('id' => $item, 'aantal' => 1);
$last = $item;
}
}
// last pass
if ($current) {
$result[] = $current;
}
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