C++ 二维数组到一维数组 [英] C++ 2D array to 1D array

问题描述

我正在尝试将二维数组转换为一维数组.我对 C/C++ 非常陌生，但我认为学习如何将 2D 数组转换为 1D 非常重要.所以我在这里遇到了这个问题.

I am attempting to convert a 2D array to 1D. I'm extremely new to C/C++ but I think it's very important to learn how to convert a 2D array to 1D. So here I am stumbling upon this problem.

到目前为止我的代码是http://ideone.com/zvjKwP

#include<iostream>

using namespace std;

int main()
{

int n=0,m=0; // 2D array nRow, nCol
int a[n][m];
int i,j; // цикъл въвеждане 2D
int q,p,t; // for 2D=>1D
int b[100];
int r; // for cout
cout<<"Enter the array's number of rows and columns: ";
cin>>n>>m;

// entering values for the 2D array
    for (i = 0;i<=n;i++)
    {
        for (j = 0;j<=m;j++)
        {
            cout<<"a["<<i<<"]["<<j<<"]="<<endl;
            cin>>a[i][j];
            cin.ignore();
        }
    }

  // Most likely the failzone IMO
  for (q = 0;q<=i;q++)
    {
        for (t = 0;t<=i*j+j;t++)
        {
            b[t] = a[i][j];
        }
    }
    // attempting to print the 1D values
     cout<<"The values in the array are"<<"\n";
    for(r=0;r<=t;r++)
    {
        cout<<"b["<<r<<"] = "<<b[r]<<endl;
    }

    cin.get();
    return 0;
    }

我在我认为我失败的地方写了一条评论.

I wrote a comment at where I think I fail.

我还必须将进入 1D 的数字限制为 value^2 大于 50 的数字.但可以肯定的是，我必须解决转换 2D=>1D 的问题你能帮我吗?

I must also limit the numbers that get into the 1D to numbers who's value^2 is greater than 50. But for sure I must solve the problem with the conversion 2D=>1D Can you help me out?

推荐答案

你的假设是对的:

循环应该是这样的:

for (q = 0; q < n; q++)
{
    for (t = 0; t < m; t++)
    {
        b[q * m + t] = a[q][t];
    }
}

从更高维数组的角度考虑这种转换总是更容易.此外，对于您的代码，您实际上并未在 b 分配周期中修改 i 或 j，因此您不应期望将不同的值分配给b 的不同数组成员.

It is always easier to consider such conversions from the view point of the higher dimension array. Furthermore with your code you did not actually modify i or j in the b assigning cycle, so you should not expect different values to be assigned to the different array members of b.

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