分配使得指针从int瓦特/出一个投 [英] Assignment makes pointer from int w/out a cast

问题描述

我编译一些code为memoizes Fibonacci数的程序。该项目工程完美然而，当我在Linux环境下编译我在编译之前得到这样的警告。

I am compiling some code for a program that memoizes fibonacci numbers. The program works perfectly however when I compile in linux environment I get this warning before compiling.

line 61: warning: assignment makes pointer from integer without a cast [enabled by default]

下面是此警告的是来自的code的片段，我会尽力展现最相关的事情，才能psented形势最好的图片$ P $

Here is a snippet of code of where this warning is coming from, I'll try to show things of most relevance to get the best picture presented of the situation

int InitializeFunction(intStruct *p, int n)

    p->digits = (int)malloc(sizeof(int) * 1);

        if(p->digits == NULL)
            handleError("Got error");

    //making the one index in p->digits equal to n
    p->digits[0] = n;

    //incrementing a field of 'p'
    p->length++;

    //return 1 if successful
    return 1;

此功能仅一个非常特定的目的叫了两声。它是用来初始化两个基例Fibonacci序列F [0] = 0＆安培; F [1] = 1，这是它的唯一目的。所以，如果我通过引用传递特定的索引的地址结构的数组，它只是应该初始化这些值：

This function is only called twice for a very specific purpose. it is used to initialize the two base cases in the fibonacci sequence f[0] = 0 & f[1] = 1. That's it's only purpose. So if I pass by reference the address of a specific index in an array of structs it's just supposed to initialize those values:

Initializer(&someIntStruct[0], 0) ---->  after function -> someIntStruct[0] == 0
Initializer(&someIntStruct[1], 1) ---->  after function -> someIntStruct[1] == 1

想法？

推荐答案

改变

p->digits = (int)malloc(sizeof(int) * 1);

到

p->digits = (int*)malloc(sizeof(int) * 1);

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