重写JSON字符串 - 由分组值键到一个新的数组？ [英] Rewriting a JSON string - grouping keys by value into a new array?

问题描述

好吧，我有一个JSON字符串：

Ok, I have a JSON string:

[{
"Name": "Title 1",
"Count1": 556,
"Count2": 5,
"Date": "2012-12-05"
}, {
"Name": "Title 2",
"Count1": 10,
"Count2": 100,
"Date": "2012-12-05"
}, {
"Name": "Title 3",
"Count1": 798,
"Count2": 11,
"Date": "2012-12-04"
}...

和我运行上json_de code，得到一个数组，现在我想通过该数组来运行和计算共1个记录和汇总共2个记录每个日期...（和日期可以去无论什么范围）。什么是这样做的最快/ niftiest方式？

and I run json_decode on that, get an array, and now I want to run through that array and calculate totals for Count1 and Count2 for each date... (and the dates can go on for whatever range). What's the fastest/niftiest way of doing that?

通过在f​​oreach每个键=> VAL杆，然后莫名其妙组日期键进入新数组中的一个新的密钥，并添加在里面的总数，让我得到这个为输出排序循环，在最末尾的JSON饲料，后json_en code，按日期排序：

Sort of loop through each key => val par in a foreach, and then somehow group the date keys into a new key in a new array and add the totals in there, so that I'm getting this as an output, in JSON feed at the very end, after json_encode, sorted by date:

[{
"Date": "2012-12-05"
"TotalCount1": 566,
"TotalCount2": 105,
}, {
"Date": "2012-12-04"
"TotalCount1": 798,
"TotalCount2": 11,
}...

我将如何群发整个阵列json_en code之前数组值这样？

how would I group the array values like that before sending the whole array to json_encode?

推荐答案

我觉得用 $总计数组索引你的日期将在这里工作（如果我理解正确的话）。如下图所示，其中 $数据的例子东西是你的德codeD 关联JSON数组：

I think using a $totals array indexed on your date would work here (if I understand you correctly). Something like the example below where $data is your decoded associative JSON array:

$totals = array();

foreach ($data as $row) {
    if (isset($totals[$row['Date']]) ) {

        $totals[$row['Date']]['TotalCount1']
            = $totals[$row['Date']]['TotalCount1'] + $row['Count1'];

        $totals[$row['Date']]['TotalCount2']
            = $totals[$row['Date']]['TotalCount2'] + $row['Count2'];

    } else {

        $totals[$row['Date']] = array(
             'Date' => $row['Date'],
             'TotalCount1' => $row['Count1'],
             'TotalCount2' => $row['Count2'],
        );

    }
}

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