盒子<T>Rust 中的 &T [英] Box<T> to &T in Rust

问题描述

如果我有一个 Box<T>，我该如何调用需要 trait 对象的函数?换句话说:

How do I call a function that expects a trait object if I have a Box<T> instead? In other words:

trait T { ... }

fn func(t: &T) { ... }

fn some_other_func() {
   b: Box<T>; // Provided

   // These work, but is there a better way?
   func( &*b );                // 1
   func( Borrow::borrow(&b) ); // 2
}

1 和 2 似乎都错了.我是否遗漏了一些明显的东西?

Both 1 and 2 seem wrong. Am I missing something obvious?

推荐答案

&*foo 被称为重新借用"，是惯用的.

&*foo is called a "reborrow", and is idiomatic.

这篇关于盒子<T>Rust 中的 &T的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！