XML 文件中不同节点的 XSL [英] XSL for each for different nodes in XML file
本文介绍了XML 文件中不同节点的 XSL的处理方法，对大家解决问题具有一定的参考价值，需要的朋友们下面随着小编来一起学习吧！
问题描述
这是我的 XML:
<?xml version="1.0" encoding="UTF-8"?>
<?xml-stylesheet type="text/xsl" href="coursestyle.xsl"?>
<s:Envelope xmlns:s="http://schemas.xmlsoap.org/soap/envelope/">
<s:Body>
<ns0:FindCoursesForOffenderResponse xmlns:ns0="http://H.FindCoursesForOffenderResponse">
<ns0:SiteList>
<ns0:SiteEntity>
<ns0:SiteId>10</ns0:SiteId>
<ns0:SiteName>Ramada Watford</ns0:SiteName>
</ns0:SiteEntity>
<ns0:SiteEntity>
<ns0:SiteId>20</ns0:SiteId>
<ns0:SiteName>Ramada Jarvis (Comet) Hotel</ns0:SiteName>
</ns0:SiteEntity>
</ns0:SiteList>
<ns0:CourseList>
<ns0:CourseEntity>
<ns0:CourseId>50</ns0:CourseId>
<ns0:SiteId>10</ns0:SiteId>
</ns0:CourseEntity>
<ns0:CourseEntity>
<ns0:CourseId>10</ns0:CourseId>
<ns0:SiteId>10</ns0:SiteId>
</ns0:CourseEntity>
<ns0:CourseEntity>
<ns0:CourseId>20</ns0:CourseId>
<ns0:SiteId>20</ns0:SiteId>
</ns0:CourseEntity>
</ns0:CourseList>
</ns0:FindCoursesForOffenderResponse>
</s:Body>
</s:Envelope>
我想为每个 CourseEntity 选择 SiteName.例如，对于 CourseID = 50，SiteName 应该是 Ramada Watford.
I want to select the SiteName for each CourseEntity. For example for the CourseID = 50 the SiteName should be Ramada Watford.
到目前为止我有这个 XSL，但它不起作用.
So far I have this XSL but it doesn't work.
<?xml version='1.0'?>
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform" xmlns:ns0="http://H.FindCoursesForOffenderResponse" xmlns:s="http://schemas.xmlsoap.org/soap/envelope/">
<xsl:output method="html"/>
<xsl:param name="lnum">123</xsl:param>
<xsl:template match="/">
<html>
<body>
<ul>
<xsl:for-each select="s:Envelope/s:Body/ns0:FindCoursesForOffenderResponse/ns0:CourseList/ns0:CourseEntity">
<xsl:variable name="currEntity"><xsl:value-of select="ns0:SiteId"/></xsl:variable>
<xsl:value-of select="$currEntity"/><br/>
<xsl:for-each select="s:Envelope/s:Body/ns0:FindCoursesForOffenderResponse/ns0:SiteList/ns0:SiteEntity[ns0:SiteId=$currEntity]">
<li>
<xsl:value-of select="ns0:SiteName"/>
</li>
</xsl:for-each>
</xsl:for-each>
</ul>
</body>
</html>
</xsl:template>
</xsl:stylesheet>
第一个 for-each 循环通过 CourseEntities 运行，内部循环试图找到每个课程 ID 的相关站点名称.
The first for-each loop runs through CourseEntities and the inner loop is trying to find the relevant site name for each course id.
有什么想法吗?
输出
<couseID> - <sitename>
50 - Ramada Watford
20 - Ramada Jarvis (Comet) Hotel
推荐答案
在 XSLT 中通常最好避免 For-each 循环.试试这种模板化方法.
For-each loops are normally best avoided in XSLT. Try this templated approach.
<!-- kick things off -->
<xsl:template match="s:Envelope/s:Body/ns0:FindCoursesForOffenderResponse">
<ul>
<xsl:apply-templates select='ns0:CourseList/ns0:CourseEntity' />
</ul>
</xsl:template>
<!-- site entities... -->
<xsl:template match='ns0:CourseEntity'>
<li>
<xsl:value-of select='ns0:CourseId' />
-
<!-- ...find corresponding site name -->
<xsl:value-of select='../../ns0:SiteList/ns0:SiteEntity[ns0:SiteId = current()/ns0:SiteId]/ns0:SiteName' />
</li>
</xsl:template>
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