如何拔出从嵌套数组数据在PHP？ [英] How to pull out data from nested array in PHP?

问题描述

这是从<一个跟进的问题href=\"http://stackoverflow.com/questions/2080795/how-to-convert-array-to-list-without-in-php\">here.但问题是不同的。

我有以下的阵列输出。

 数组$事件排列
（
    [0] =＆GT;排列
        （
            [日] =＆GT; 17
            [eventContent] =＆GT; 17日的事件1
            [EVENTTITLE] =＆GT; 17事件1
        ）    [1] =＆GT;排列
        （
            [日] =＆GT; 19
            [eventContent] =＆GT; 19日的事件1
            [EVENTTITLE] =＆GT; 19事件1
        ）    [2] =＆GT;排列
        （
            [日] =＆GT; 05
            [eventContent] =＆GT; 5日的事件1
            [EVENTTITLE] =＆GT; 5事件1
        ）    [3] =＆GT;排列
        （
            [日] =＆GT; 17
            [eventContent] =＆GT; 17日事件2
            [EVENTTITLE] =＆GT; 17日事件2
        ）    [4] =＆GT;排列
        （
            [日] =＆GT; 19
            [eventContent] =＆GT; 19日事件2
            [EVENTTITLE] =＆GT; 19事件2
        ）    [5] =＆GT;排列
        （
            [日] =＆GT; 19
            [eventContent] =＆GT; 19日3时
            [EVENTTITLE] =＆GT; 19日事件3
        ））
 

和我想拉奏的一天。

如果我用这个，它会拿起1,2,3等，但我想17，19等。

 如果（array_key_exists（$天，$事件））{...
 

任意子能告诉我该怎么做吗？

先谢谢了。

- 更新 -

我需要修改原始视图。

 如果（array_key_exists（$天，$事件））
{//添加date_has_event类的＆lt; TD＆GT;并关闭它
回声级=date_has_event＆GT; 。'$日;
//添加EVENTTITLE和eventContent包裹在里面＆LT;跨度＆GT; ＆安培; ＆LT;立GT;到＆lt; UL＆GT;
呼应'＆LT; D​​IV CLASS =事件＆GT;＆LT; UL＆GT;';？＆GT;
？＆LT; PHP的foreach（$事件$事件）：GT;？
＆LT;立GT;
＆LT;跨度类=标题＆GT;＆LT; PHP的echo $事件['EVENTTITLE']; ？＆GT;＆LT; / SPAN＆GT;
＆LT;跨度类=降序＆GT;＆LT; PHP的echo $事件['eventContent']; ？＆GT;＆LT; / SPAN＆GT;
＆LT; /李＆GT;
＆LT; PHP endforeach; ？＆GT;＆LT; PHP
呼应'＆LT; / UL＆GT;＆LT; / DIV＆GT;';
}
 

解决方案

试试这个：

  $ eventsByDay =阵列（）;
的foreach（$事件$关键=＆GT; $事件）{
    如果（！使用isset（$ eventsByDay [$事件['天']））{
        $ eventsByDay [$事件['天'] =阵列（）;
    }
    $ eventsByDay [$事件['天'] [] = $事件;
}
 

$ eventsByDay 现在是一个数组，其中最关键的是白天和值是对应的事件数组。

This is a follow up question from here. But question is different.

I have the following array outputs.

Array $events

Array
(
    [0] => Array
        (
            [day] => 17
            [eventContent] => event 1 of 17th
            [eventTitle] => 17th event 1
        )

    [1] => Array
        (
            [day] => 19
            [eventContent] => event 1 of 19th
            [eventTitle] => 19th event 1
        )

    [2] => Array
        (
            [day] => 05
            [eventContent] => event 1 of 5th
            [eventTitle] => 5th event 1
        )

    [3] => Array
        (
            [day] => 17
            [eventContent] => event 2 of 17th
            [eventTitle] => 17th event 2
        )

    [4] => Array
        (
            [day] => 19
            [eventContent] => event 2 of 19th
            [eventTitle] => 19th event 2
        )

    [5] => Array
        (
            [day] => 19
            [eventContent] => event 3 of 19th
            [eventTitle] => 19th event 3
        )

)

And I want to pull outs day.

If I use this, it will pick up 1,2,3 etc. But I want 17, 19 etc.

if(array_key_exists($day,$events)){...

Could anyon tell me how to do it please?

Thanks in advance.

--UPDATE--

Original view which I need to modify.

if(array_key_exists($day,$events))
{

//adding the date_has_event class to the <td> and close it
echo ' class="date_has_event"> '.$day;
//adding the eventTitle and eventContent wrapped inside <span> & <li> to <ul>
echo '<div class="events"><ul>';?>
<?php foreach ($events as $event) : ?>
<li>
<span class="title"><?php echo $event['eventTitle']; ?></span>
<span class="desc"><?php echo $event['eventContent']; ?></span>
</li>
<?php endforeach; ?>

<?php                           
echo '</ul></div>';
}

解决方案

Try this:

$eventsByDay = array();
foreach ($events as $key => $event) {
    if (!isset($eventsByDay[$event['day']])) {
        $eventsByDay[$event['day']] = array();
    }
    $eventsByDay[$event['day']][] = $event;
}

$eventsByDay is now an array where the key is the day and the value is an array of the corresponding events.

这篇关于如何拔出从嵌套数组数据在PHP？的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！