类型错误:“int"对象不可迭代 [英] TypeError: 'int' object is not iterable

问题描述

执行此代码时出错-
for i in len(str_list):类型错误:int"对象不可迭代

我该如何解决?(Python 3)

How would I fix it? (Python 3)

def str_avg(str):
    str_list=str.split()
    str_sum=0
    for i in len(str_list):
        str_sum += len(str_list[i])
    return str_sum/i

推荐答案

您正在尝试在整数中循环；len() 返回一.

You are trying to loop over in integer; len() returns one.

如果您必须在整数序列上生成循环，请使用 range() 对象:

If you must produce a loop over a sequence of integers, use a range() object:

for i in range(len(str_list)):
    # ...

通过将 len(str_list) 结果传递给 range()，你得到一个从零到 str_list 长度的序列，减一(因为不包括最终值).

By passing in the len(str_list) result to range(), you get a sequence from zero to the length of str_list, minus one (as the end value is not included).

请注意，现在您的 i 值将是用于计算平均值的不正确值，因为它比实际值小一列表长度！你想除以len(str_list):

Note that now your i value will be the incorrect value to use to calculate an average, because it is one smaller than the actual list length! You want to divide by len(str_list):

return str_sum / len(str_list)

但是，无需在 Python 中执行此操作.您遍历列表本身的元素.这消除了首先创建索引的需要:

However, there is no need to do this in Python. You loop over the elements of the list itself. That removes the need to create an index first:

for elem in str_list
    str_sum += len(elem)

return str_sum / len(str_list)

所有这些都可以用 sum() 在一行中表达函数，顺便说一句:

All this can be expressed in one line with the sum() function, by the way:

def str_avg(s):
    str_list = s.split()
    return sum(len(w) for w in str_list) / len(str_list)

我用s替换了名称str；最好不要屏蔽内置类型名称，否则可能会导致稍后出现混淆错误.

I replaced the name str with s; better not mask the built-in type name, that could lead to confusing errors later on.

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