类型错误:无法在 Django 视图函数中解压不可迭代的 int 对象 [英] TypeError: cannot unpack non-iterable int object in Django views function

问题描述

以下是我在 URL.py、views.py 和 HTML 页面中的代码.但是，它返回了错误:TypeError: cannot unpack non-iterable int object.

Following is my code in URL.py, views.py and HTML page. However, it returns me the error: TypeError: cannot unpack non-iterable int object.

urlpatterns = [
    path('', views.blogs_home, name='blogs'),
    path('<int:id>', views.single_blog, name='detailed_view'),

]

我试图在列表视图中捕获帖子博客的 id，以使用 id 查询从数据库中获取博客对象.以下是我的查看代码.

I am trying to capture the id of posts blogs in the list view to get the blog object from the database with id query. Following is my view code.

def single_blog(request,id):
   blog_single = Blogs.objects.get(id)
   context = {'blog_single': blog_single}
   template = 'blog_home.html'

   return render(request, template, context)

但是，正如我所提到的，它返回上述错误.

However, as I mentioned, it returns the above error.

谁能解释一下我做错了什么

Could someone explain what I am doing wrong

推荐答案

您应该在 .filter(..) 或 .get(..)<中指定参数的名称/code> 调用:

You should specify the name of the parameter in .filter(..) or .get(..) calls:

def single_blog(request, id):
   blog_single = Blogs.objects.get(id=id)
   context = {'blog_single': blog_single}
   template = 'blog_home.html'

   return render(request, template, context)

我还建议将您的变量重命名为其他名称(因此在 urls.py 和 views.py 中)，因为 id是一个内置函数，现在一个局部变量隐藏"了这个内置函数.

I also propose to rename your variable to something else (so both in the urls.py and views.py), since id is a builtin function, and now a local variable is "hiding" this builtin.

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