Python:为什么比较 int 与字符串的相等性不会引发错误? [英] Python: Why does equality comparing an int with a string not throw an error?

问题描述

在 Python 3 中，尝试对字符串和 int 进行排序(例如 1 > "1")会引发 TypeError.为什么将字符串与 int 进行比较不会引发错误?(例如 1=="1")将字符串与 int 进行比较有意义的示例是什么?为什么 JavaScript 和 SQL 采用不同的方法?

In Python 3 the attempt to order a string and an int (e.g. 1 > "1") throws a TypeError. Why does comparing a string with an int for equality not throw an error? (e.g. 1=="1") What is an example where comparing a string with an int makes sense? Why do JavaScript and SQL take a different approach?

相关:Python 如何比较字符串和整数?

推荐答案

例如，这允许您拥有一个包含混合类型键的字典.

This allows you, for example, to have a dictionary with keys of mixed types.

如果您无法比较 1 和 "1" 是否相等，您将无法将它们用作同一字典中的键.

If you couldn't compare 1 and "1" for equality, you wouldn't be able to use them as keys into the same dictionary.

就目前情况而言，您可以比较它们，它们总是比较不平等:

As things stand, you can compare them, and they always compare unequal:

对象不必具有相同的类型.如果两者都是数字，则将它们转换为公共类型.否则，不同类型的对象总是比较不相等，并且顺序一致但随意.

The objects need not have the same type. If both are numbers, they are converted to a common type. Otherwise, objects of different types always compare unequal, and are ordered consistently but arbitrarily.

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