使用hashCode（）测试字符串相等性 [英] Testing string equality using hashCode()
问题描述
有没有理由不能使用hashCode方法测试Java字符串的相等性？所以基本上，而不是....
Is there any reason why a Java string cannot be tested for equality using it's hashCode method? So basically, instead of....
"hello".equals("hello")
您可以使用...
"hello".hashCode() == "hello".hashCode()
这将是有用，因为一旦字符串计算了它的哈希码，那么比较一个字符串就像比较一个int一样有效，因为字符串缓存了哈希码，而且如果你那样设计它，很可能字符串在字符串池中。 / p>
This would be useful because once a string has calculated it's hashcode then comparing a string would be as efficient as comparing an int as the string caches the hashcode and it is quite likely that the string is in the string pool anyway, if you designed it that way.
推荐答案
因为：如果对象相等，两个对象的hashCodes必须相等，但是，如果两个对象不相等，hashCode可以仍然是平等的。
because: hashCodes of two objects must be equal if the objects are equal, however, if two objects are unequal, the hashCode can still be equal.
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