在MATLAB重塑阵列 [英] Reshaping arrays in MATLAB

问题描述

我有1024大小为1024的二进制数组3D由1024我想用一个函数（ convhull ），它具有以下输入：

I have a binary 3D array of the size 1024 by 1024 by 1024. I want to use a function (convhull), which has the following input:

X是大小MPTS逐NDIM，其中MPTS是点和NDIM的数量是其中点所在的空间，2≦NDIM≦3 ​​

X is of size mpts-by-ndim, where mpts is the number of points and ndim is the dimension of the space where the points reside, 2 ≦ ndim ≦ 3

我怎样才能重塑我的数组，由本功能的阵列型X？

How can I reshape my array into the array X which is required by this function?

也许重塑是不是最好的词，因为使用重塑的功能是远远不够的。

Maybe "reshape" isn't the best word, because using the "reshape" function isn't enough.

推荐答案

什么 convhull 正在寻找的是你的数组中的非零元素的下标列表。给定一个三维数组 M ：

What convhull is looking for is a list of subscripts of nonzero elements in your array. Given a 3D array M:

[X,Y,Z] = ind2sub(size(M), find(M));

然后使用这些在 convhull ：

convhull(X, Y, Z);

您在你的问题提的孤独 X 参数仅仅是串联这三个列向量：

The lone X parameter you mention in your question is just these three column vectors concatenated:

X = [X Y Z];
convhull(X);

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