Java的ARGS不兼容的类型 [英] Java args Incompatible types

问题描述

对不起，我是一个Java小白。任何想法，为什么我的code未编制？
我想它的工作，这样我可以在命令行中输入两个数组，并让他们使用的findNa的方法。如果数组元素的比赛，我想NA要打印一个新行，如果没有比赛，我想在阵的原始值进行打印。
在此先感谢！

 类naFam {
    静态无效findNa（String []数组，字符串[] lookupArray）{
        INT I;
        诠释J;
        对于（i = 0; I＆LT; array.length，我++）{
            为（J = 0; J＆LT; lookupArray.length; J ++）{
                如果（阵列[我] == lookupArray [J]）{
                    的System.out.println（NA）;
                }其他{
                    的System.out.println（数组[我]）;
                }
            }
        }
    }
    公共静态无效的主要（字符串ARGS []）{
        String []数组= ARGS [0];
        的String [] = lookupArray ARGS [1];
        findNa（数组，lookupArray）;    }
}
 

解决方案

  String []数组= ARGS [0];
 

您要设置一个数组等于一个字符串（ ARGS [0] 返回字符串有的0阵列内的索引）。

同样在这里：

 的String [] = lookupArray ARGS [1];
 

如果您想输入2个数组，然后检查他们是平等的尝试是这样的：

 进口java.util.Scanner中;类naFam {
    静态无效findNa（String []数组，字符串[] lookupArray）{
        布尔等于= TRUE;
        的for（int i = 0; I＆LT; array.length，我++）{
            如果（阵列[I]！= lookupArray [I]）{
                等于= FALSE;
            }
        }
        如果（等于==真）{
             的System.out.println（NA）;
        }其他{
            的System.out.println（数组[0]）;
        }
    }    公共静态无效的主要（字串[] args）{
        //创建一个新的扫描仪
        扫描程序扫描=新的扫描仪（System.in）;
        //创建他们想输入的数组的大小的整数
        INT尺寸1;
        //输入的大小
        尺寸1 = scan.nextInt（）;
        //创建并输入数组
        的String [] = arrayOne新的String [尺寸1];
        的String [] = arrayTwo新的String [尺寸1];        的for（int i = 0; I＆LT;尺寸1，我++）{
            arrayOne [I] = scan.next（）;
        }
        的for（int i = 0; I＆LT;尺寸1，我++）{
            arrayTwo [I] = scan.next（）;
        }
        findNa（arrayOne，arrayTwo）;
    }
}
 

没有测试它尚未但它应该工作。

Sorry, I'm a Java noob. Any idea why my code isn't compiling? I would like it to work such that I can enter two arrays at the command line, and have them used by the "findNa" method. If elements in the array match I would like NA to be printed on a new line, if there is no match I would like the original value in "array" to be printed. Thanks in advance!

  class naFam {
    static void findNa(String[] array, String[] lookupArray) {
        int i;
        int j;
        for (i = 0; i < array.length; i++) {
            for (j = 0; j < lookupArray.length; j++) {
                if (array[i] == lookupArray[j]) {
                    System.out.println("NA");
                } else {
                    System.out.println(array[i]);
                }
            }
        }
    }
    public static void main(String args[]) {
        String[] array = args[0];
        String[] lookupArray = args[1];
        findNa(array, lookupArray);

    }
}

解决方案

String[] array = args[0];

You are setting an array to be equal to a string (args[0] returns the String which has the index of 0 inside the array).

Same here:

String[] lookupArray = args[1];

If you want to input 2 arrays and then check if they're equal try something like this:

import java.util.Scanner;

class naFam {
    static void findNa(String[] array, String[] lookupArray) {
        boolean equal = true;
        for (int i = 0; i < array.length; i++) {
            if (array[i]!=lookupArray[i]) {
                equal=false;
            }
        }
        if (equal==true) {
             System.out.println("NA");
        } else {
            System.out.println(array[0]);
        }
    }

    public static void main(String[] args) {
        //Create a new scanner
        Scanner scan = new Scanner(System.in);
        //Create the integer for the size of the array they want to input
        int size1;
        //Input the size
        size1 = scan.nextInt();
        //Create and input the arrays
        String[] arrayOne = new String[size1];
        String[] arrayTwo = new String[size1];

        for (int i = 0; i < size1; i++) {
            arrayOne[i] = scan.next();
        }
        for (int i = 0; i < size1; i++) {
            arrayTwo[i] = scan.next();
        }
        findNa(arrayOne,arrayTwo);
    }
}

Haven't tested it yet but it should work.

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