如何在Java中解决这种不兼容的类型？ [英] How to solve this incompatible types in java?

问题描述

 错误：不兼容的类型
 required：java.util.Map。条目< java.lang.String中，java.lang.String中[] GT; 
 found：java.lang.Object 
  

完整代码低于

  package com.auth.actions; 
 
 public class SocialAuthSuccessAction extends Action {
 
 final Log LOG = LogFactory.getLog（SocialAuthSuccessAction.class）; 
 $ b @Override 
 public ActionForward execute（最终ActionMapping映射，
最终ActionForm表单，最终HttpServletRequest请求，$ b $最终HttpServletResponse响应）throws Exception {
 
 AuthForm authForm =（AuthForm）表单; 
 SocialAuthManager manager = null; 
 if（authForm.getSocialAuthManager（）！= null）{
 manager = authForm.getSocialAuthManager（）; 
} 
 if（manager！= null）{
 List< Contact> contactsList = new ArrayList< Contact>（）; 
配置文件配置文件= null; 
尝试{
 Map< String，String> paramsMap = new HashMap< String，String>（）; 
 for（Map.Entry< String，String []> entry：request.getParameterMap（）。entrySet（））{//此错误！ 
 String key = entry.getKey（）; 
字符串值[] = entry.getValue（）; 
 paramsMap.put（key，values [0] .toString（））; //只有1个值是
} 
 AuthProvider provider = manager.connect（paramsMap）; 
 
 profile = provider.getUserProfile（）; 
 contactsList = provider.getContactList（）; （ContactList！= null&& contactsList.size（）> 0）{
 for（Contact p：contactsList）{
 if（StringUtils.isEmpty（p.getFirstName ））
&& StringUtils.isEmpty（p.getLastName（）））{
 p.setFirstName（p.getDisplayName（））; 
} 
} 
} 
} catch（Exception e）{
 e.printStackTrace（）; 
} 
 request.setAttribute（profile，profile）; 
 request.setAttribute（contacts，contactsList）; 
 
返回mapping.findForward（success）; 
} 
 // if provider null 
 return mapping.findForward（failure）; 
 
 
 $ / code $ / pre 
 $ b $ p请帮忙
 <您需要将 request.getParameterMap（）转换为 Map< String，String 

（Map.Entry< String，String []>条目：

  
（（Map< String，String []>）request.getParameterMap（））。entrySet（））
  

I get error in following lines.

error: incompatible types
required : java.util.Map.entry<java.lang.String,java.lang.String[]>
found :java.lang.Object         

full code is below

package com.auth.actions;

public class SocialAuthSuccessAction extends Action {

    final Log LOG = LogFactory.getLog(SocialAuthSuccessAction.class);

    @Override
    public ActionForward execute(final ActionMapping mapping,
            final ActionForm form, final HttpServletRequest request,
            final HttpServletResponse response) throws Exception {

        AuthForm authForm = (AuthForm) form;
        SocialAuthManager manager = null;
        if (authForm.getSocialAuthManager() != null) {
            manager = authForm.getSocialAuthManager();
        }
        if (manager != null) {
            List<Contact> contactsList = new ArrayList<Contact>();
            Profile profile = null;
            try {
                Map<String, String> paramsMap = new HashMap<String, String>();
                for (Map.Entry<String, String[]> entry :request.getParameterMap().entrySet() ) { // error in this line!
                    String key = entry.getKey();
                    String values[] = entry.getValue();
                    paramsMap.put(key, values[0].toString()); // Only 1 value is
                }
                AuthProvider provider = manager.connect(paramsMap);

                profile = provider.getUserProfile();
                contactsList = provider.getContactList();
                if (contactsList != null && contactsList.size() > 0) {
                    for (Contact p : contactsList) {
                        if (StringUtils.isEmpty(p.getFirstName())
                                && StringUtils.isEmpty(p.getLastName())) {
                            p.setFirstName(p.getDisplayName());
                        }
                    }
                }
            } catch (Exception e) {
                e.printStackTrace();
            }
            request.setAttribute("profile", profile);
            request.setAttribute("contacts", contactsList);

            return mapping.findForward("success");
        }
        // if provider null
        return mapping.findForward("failure");
    }
}

Please help

解决方案

You need to cast request.getParameterMap()to Map<String, String[]>

for (Map.Entry<String, String[]> entry :
     ((Map<String, String[]>)request.getParameterMap()).entrySet())

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