如何从 UML 中的模板参数表示继承? [英] How can I represent inheritance from a template parameter in UML?

问题描述

使用UML，我如何表示A<Foo > 在下面的代码中?

Using UML, how can I represent A< Foo > in the following code?

template< class T > 
class A : public T
{
    /* ... */
};

class Foo { };

A< Foo > a_foo;

这样的事情(为糟糕的 ascii 艺术道歉......以及Jon Skeet) 是我的第一个猜测，但我怀疑它不正确.

Something like this (apologies for the poor ascii art... and to Jon Skeet) is my first guess, but I suspect it is not correct.

            ________________
            |              |
            |              |
            |     Foo      |
            |              |
            |______________|
             /:\  /|\
«bind»(Foo)   :    |
              :    |   .......               
            __:____|___:  T  :
            |          :.....:
            |              |
            |      A       |
            |              |
            |______________|

推荐答案

有一个提案，由 U.M.L.设计师，但是，它还不是标准的一部分.

There is a proposal, by the U.M.L. designers, but, its not part of the standard, yet.

如果没有任何模板参数，A"类型的对象a"可能是这样的:

If, there wasn't any template parameters, the object "a" of type "A", may be like this:

+--------------------+
|        a: A        | 
+--------------------+
| [+] doSomething(); |
+--------------------+

对象a"，是a"的模板，带有类型参数Foo"，可以这样表示:

The object "a", who is a template of "a", with the type parameter "Foo", may be represented like this:

                  +-----+
+-----------------| Foo |
|                 +-----+
|        a: A        | 
+--------------------+
| [+] doSomething(); |
+--------------------+

请注意，在 U.M.L. 中，当您声明一个类时，它们由一个矩形表示，而特定的对象，例如a"，则由带有圆角的矩形表示.有些人，&工具，不遵循圆角"规范.

Note, that, in U.M.L., when you declare a class, they are represented by a rectangle, while specific objects, such "a", are represented by rectangle with round corners. Some people, & tools, doesn't follow the "round corners" specification.

干杯.

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