通过指针算法访问结构数据成员 [英] Accessing struct data members via pointer arithmetic
问题描述
如果我有一个像这样的简单张量类
If I have a simple tensor class like this
struct Tensor
{
double XX, XY, XZ;
double YX, YY, YZ;
double ZX, ZY, ZZ;
}
使用指针算术(见下文)访问其元素是否是未定义的行为?
Is it undefined behavior to use pointer-arithmetic (see below) to access its elements?
double& Tensor::operator[](int i)
{
assert(i < 9);
return (&XX)[i];
}
推荐答案
是的,这是未定义的行为.
Yes, it is undefined behavior.
数据成员不在数组中,因此不能保证在连续内存中背靠背存储,因为指针运算需要.它们之间可能会产生不确定的填充.
The data members are not in an array, and thus are NOT guaranteed to be stored back-to-back in contiguous memory, as pointer arithmetic would require. There may be indeterminate padding generated between them.
正确的方法是单独访问成员,例如:
The correct way would be to access the members individually, eg:
double& Tensor::operator[](int i)
{
switch (i)
{
case 0: return XX;
case 1: return XY;
case 2: return XZ;
case 3: return YX;
case 4: return YY;
case 5: return YZ;
case 6: return ZX;
case 7: return ZY;
case 8: return ZZ;
default: throw std::out_of_range("invalid index");
}
}
或者,如果你真的想使用数组语法:
Alternatively, if you really want to use array syntax:
double& Tensor::operator[](int i)
{
if ((i < 0) || (i > 8))
throw std::out_of_range("invalid index");
double* arr[] = {
&XX, &XY, &XZ,
&YX, &YY, &YZ,
&ZX, &ZY, &ZZ
};
return *(arr[i]);
}
或
double& Tensor::operator[](int i)
{
if ((i < 0) || (i > 8))
throw std::out_of_range("invalid index");
static double Tensor::* arr[] = {
&Tensor::XX, &Tensor::XY, &Tensor::XZ,
&Tensor::YX, &Tensor::YY, &Tensor::YZ,
&Tensor::ZX, &Tensor::ZY, &Tensor::ZZ
};
return this->*(arr[i]);
}
否则,对数据使用实际数组,并定义访问元素的方法:
Otherwise, use an actual array for the data, and define methods to access the elements:
struct Tensor
{
double data[9];
double& XX() { return data[0]; }
double& XY() { return data[1]; }
double& XZ() { return data[2]; }
double& YX() { return data[3]; }
double& YY() { return data[4]; }
double& YZ() { return data[5]; }
double& ZX() { return data[6]; }
double& ZY() { return data[7]; }
double& ZZ() { return data[8]; }
double& operator[](int i)
{
if ((i < 0) || (i > 8))
throw std::out_of_range("invalid index");
return data[i];
}
};
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