如何拆分成整数使用Java数组？ [英] How to split an Integer into an Array using Java?

问题描述

我道歉，如果这已经被问过，但我无法找到经过一番搜索大量确凿的答案，所以我想我会问这里。我是一个初学者到Java（编码，在一般情况），并编写一个程序，需要用户输入3位数字，并增加了这三个数字受命。

注：我不能循环使用此任务，三个数字必须一次全部输入。

 字符串myInput;
    myInput =
    JOptionPane.showInputDialog（NULL，你好，欢迎到ThreeDigit程序。
    +\\ n请输入以下三个数字\\ nThreeDigit将增加这三个数字并显示它们的总和。）;
    INT threedigitinput;
    threedigitinput =的Integer.parseInt（myInput）;
 

解决方案

有多种方式，其中之一将是...

 字符串SS [] =123.split（）;
    INT I =
            的Integer.parseInt（β[0]）+
            的Integer.parseInt（β[1]）+
            的Integer.parseInt（β[2]）;
    的System.out.println（ⅰ）;
 

另一个是...

 一个String =123;
    INT I =
            Character.getNumericValue（s.charAt（0））+
            Character.getNumericValue（s.charAt（1））+
            Character.getNumericValue（s.charAt（2））;
    的System.out.println（ⅰ）;
 

还有一个是...

 一个String =123;
    INT I =
            s.charAt（0）+
            s.charAt（1）+
            s.charAt（2） - 
            （3 * 48）;
    的System.out.println（ⅰ）;
 

但硬编码的3个数字是不是超出了简单的情况下非常有用的。因此，如何递归??

 公共静态INT addDigis（String s）将{
        如果（s.length（）== 1）
            返回s.charAt（0） -  48;
        返回s.charAt（0） -  48±addDigis（s.substring（1，s.length（）））;
}
 

  

每个示例输出：6

I apologise if this has already been asked before, but I was unable to find a conclusive answer after some extensive searching, so I thought I would ask here. I am a beginner to Java (to coding, in general) and was tasked with writing a program that takes a user-inputted 3 digit number, and adds those three digits.

Note: I cannot use loops for this task, and the three digits must all be inputted at once.

String myInput;
    myInput =        
    JOptionPane.showInputDialog(null,"Hello, and welcome to the ThreeDigit program. "
    + "\nPlease input a three digit number below. \nThreeDigit will add those three numbers and     display their sum.");
    int threedigitinput;
    threedigitinput = Integer.parseInt(myInput);

解决方案

There are a number of ways, one of which would be...

    String ss[] = "123".split("");
    int i = 
            Integer.parseInt(ss[0]) + 
            Integer.parseInt(ss[1]) + 
            Integer.parseInt(ss[2]);
    System.out.println(i);

another would be...

    String s = "123";
    int i = 
            Character.getNumericValue(s.charAt(0)) +
            Character.getNumericValue(s.charAt(1)) +
            Character.getNumericValue(s.charAt(2));
    System.out.println(i);

and still another would be...

    String s = "123";
    int i = 
            s.charAt(0) +
            s.charAt(1) +
            s.charAt(2) - 
            (3 * 48);
    System.out.println(i);

BUT hard coding for 3 numbers isn't very useful beyond this simple case. So how about recursion??

public static int addDigis(String s) {
        if(s.length() == 1)
            return s.charAt(0) - 48;
        return s.charAt(0) - 48 + addDigis(s.substring(1, s.length()));
}

Output for each example: 6

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