C ++如何将它拆分成向量并使用它 [英] C++ How do i split this into vector and use it

问题描述

可能重复：

使用C ++拆分字符串

使用C ++编程。

我的客户端发送一个值为

的字符串

  string receiveClient =auth＃user：pass; 
  

如何拆分 receiveClient '＃'和'：' >

我试图使用这个在线找到的函数

  string& s，char delim）
 {
 vector string elems; 
 return（s，delim，elems）; 
} 
  

code>：

 向量x = split（& receiveClient，＃）; 
  

但它返回下列

：

  server.cpp：在函数'int main（）'：
 server.cpp：128：8：错误：在'x'之前缺少模板参数
 server.cpp ：128：8：error：expected';'before'x'
 root @ ubuntu：/ home / baoky / csci222_assn2＃g ++ server server.cpp 
 server.cpp：47：1：error：invalid使用template-name'std :: vector'没有参数列表
 server.cpp：在函数'int main（）'：
 server.cpp：128：8：error： 'x'
 server.cpp：128：8：error：expected';'before'x'
  

$ b b

感谢您的帮助。非常感谢

解决方案

这样的任务通常是最容易使用C ++中的流。这样的东西应该工作：

  //小心，大脑编译代码！ 
 
 #include< vector> 
 #include< string> 
 #include< sstream> 
 
 std :: vector< string> splitClientAuth（const std :: string& receiveClient）
 {
 //auth＃user：pass
 std :: istringstream iss（receiveClient）; 
 
 std :: vector< std :: string>字符串; 
 strings.resize（3）; 
 std :: getline（iss，strings [0]，'＃'）; 
 std :: getline（iss，strings [1]，'：'）; 
 std :: getline（iss，strings [2]）; // default is'\\\
'
 
 if（！iss&&！iss.eof（））
 throwDude，you veryly need an error handling strategy！ 
 
 if（string [0] .empty（）|| string [1] .empty（）|| string [2] .empty（））
 throwWatcha gonna do now？ ; 
 
返回字符串; 
} 
  

---

注意：

• 这些是真的 纯文字密码 吗？




• 在 std :: vector< std :: string> 如果这是我的代码，我想要 数据结构来存储用户信息 ，并写入我写的东西。




• 判断你完全不理解你在你的问题中粘贴的代码（Martinho是对的，这太糟糕了，可以说它是否仍然可以被认为是C ++ ），并根据您的意见， 您似乎不太需要良好的C ++书 。

Possible Duplicate:
Splitting a string in C++

I am doing client server programming using C++.

My client sends a string with the value

string receiveClient = "auth#user:pass";

How do I split the receiveClient variable by '#' and ':' as delimiters?

---

I have tried to use this function I found online

vector split (const string &s,char delim)
{
  vector string elems;
  return(s,delim,elems);
}

and I did this at main():

vector x = split(&receiveClient,"#");

But it return me the following

server.cpp: In function ‘int main()’:
server.cpp:128:8: error: missing template arguments before ‘x’
server.cpp:128:8: error: expected ‘;’ before ‘x’
root@ubuntu:/home/baoky/csci222_assn2# g++ server server.cpp
server.cpp:47:1: error: invalid use of template-name ‘std::vector’ without an argument list
server.cpp: In function ‘int main()’:
server.cpp:128:8: error: missing template arguments before ‘x’
server.cpp:128:8: error: expected ‘;’ before ‘x’

Thanks for all help. greatly appreciated

解决方案

Such tasks are usually easiest done using streams in C++. Something like this should work:

// Beware, brain-compiled code ahead!

#include <vector>
#include <string>
#include <sstream>

std::vector<string> splitClientAuth(const std::string& receiveClient)
{
  // "auth#user:pass"
  std::istringstream iss(receiveClient);

  std::vector<std::string> strings;
  strings.resize(3);
  std::getline(iss, strings[0], '#');
  std::getline(iss, strings[1], ':');
  std::getline(iss, strings[2]); // default is '\n'

  if( !iss && !iss.eof() )
    throw "Dude, you badly need an error handling strategy!";

  if( string[0].empty() || string[1].empty() || string[2].empty() )
    throw "Watcha gonna do now?";

  return strings;
}

---

A few additional point worth noting:

• Are those really plain-text passwords?

• Having this in a std::vector<std::string> seems dubious to me. If that was my code, I'd want a data structure to store user information, and write what I find write into that.

• Judging from you totally failing to understand the code you pasted in your question (Martinho is right, that's so bad, it's arguable whether it can still be considered C++), and from your comments, you seem to be in bad need of a good C++ book.

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