数组，结构，函数 [英] Arrays, Structs, Functions

问题描述

我需要一个结构。然后，让一个数组持有这些结构的7。再经过3个功能传递和转变职能内的结构数组的值，并将其传递回主。
我知道如何使一个结构。因此，让我们一起去的：

 结构选{
   焦炭名[20];
   INT票;
   };
 

我假设形成阵列将是：

 结构大选electionCandidates [6];
 

为了通过一个函数。我会怎么做呢？而且是更容易返回结构数组或者我应该让它通过作为一个指针？

这可能是完全不正确的，但我总觉得人们更愿意帮助，如果他们可以看到，我其实想做这个问题并不仅仅是寻求帮助，因为我懒惰或东西。

 无效初始化（选* electionCandidates []）;
 

或者，也许这一点？

 结构大选初始化（结构electionCandidates []
 

感谢您任何有用的意见。

解决方案

 无效初始化（选* electionCandidates []）;
 

语法是错误的：你必须说结构选结果。
在另一方面，您声明有其类型参数指针结构选阵，但你需要结构选阵。

所以，正确的版本是：

 无效初始化（结构大选electionCandidates []）;
 

由于函数的参数每个数组声明衰减，以指针，这将是等价于：

 无效初始化（结构大选* electionCandidates）;
 

下面的语法也是错误的：

 结构大选初始化（结构electionCandidates []
 

正确的是：

 结构大选初始化（结构大选electionCandidates []）
 

不过，这种形式不会因为你只返回1 结构看起来顺理成章。这为什么？

参数的数组元素 electionCandidates 可以通过进行修改和恢复没有任何问题的main（），所以一个无效回到这里似乎是正确的。

或许，这将是最好定义的别名键入结构选：

  typedef结构大选election_t;
 

然后我们写：

 无效初始化（election_t electrionCandidates []）
 

这将是非常可取的，你传递的候选人作为第二个参数的数量，因为函数没有办法Determina的数组大小：

 无效初始化（election_t electrionCandidates []，INT NUM）
 

然后你拨打电话是这样的：

 初始化（electionCandidates，6）;
 

在这里，神奇6号是你的数组中元素的个数。

I need to make a struct. Then make an array holding 7 of these structs. Then pass it through 3 functions and change the value of the struct array within the functions and pass it back to main. I know how to make a struct. So let's go with this:

struct election{
   char name[20];
   int votes;
   };

I'm assuming making an array would be:

struct election electionCandidates[6];

In order to pass through a function. How would I do this? And is it easier to return the struct array or should I pass it through as a pointer?

This may be completely incorrect, but I always feel like people are more willing to help if they can see that I am actually trying to do this problem and not just asking for help because I a lazy or something.

void Initialize(election *electionCandidates[]);

Or maybe this?

struct election Initialize(struct electionCandidates[]

Thank you for any helpful comments.

解决方案

   void Initialize(election *electionCandidates[]);

Syntax is wrong: you have to say struct election.
On the other hand, you are declaring there a parameter having type "pointer to array of struct election", but you need "array of struct election".

So, the correct version is:

  void Initialize(struct election electionCandidates[]);

Since in function arguments every array declaration "decays" to pointer, it would be equivalent to:

  void Initialize(struct election *electionCandidates);

The following syntax is also wrong:

  struct election Initialize(struct electionCandidates[]

The correct is:

  struct election Initialize(struct election electionCandidates[])

However, this form doesn't look as logical because you are returning only 1 struct. Which and why?

The array elements of the parameter electionCandidates can be modified and recovered without any problem by main(), so a void return here seems right.

Maybe, it would be better to define an alias for the type struct election:

  typedef struct election election_t;

Then we write:

  void Initialize(election_t electrionCandidates[])

It would be very desirable that you pass the number of candidates as a second parameter, since the function has no way to determina the array size:

  void Initialize(election_t electrionCandidates[], int num)  

Then you make the call in this way:

  Initialize(electionCandidates, 6);  

Here, the "magic" number 6 is the number of elements in your array.

这篇关于数组，结构，函数的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！