忽略顺序比较两个文件 [英] Compare two files ignoring order

问题描述

我有两个文件，行的顺序无关，我想比较其内容.

I have two files which the order of lines is irrelevant, and I want to compare its content.

我查看了 diff 文档，但找不到类似 --ignore-order 的内容.

I looked into diff documentation but could not find anything like --ignore-order.

有什么建议吗?

推荐答案

先对文件进行排序:

$ sort file1 > file1.sorted
$ sort file2 | diff - file1.sorted

此外，虽然我个人不鼓励这种事情，但如果您使用 bash 并且在您的系统上启用了此功能，您可以通过使用进程替换来避免临时文件:

Also, although I personally discourage this sort of thing, if you are using bash and this feature is enabled on your system you can avoid the temporary file by using a process substitution:

$ diff <(sort file1) <(sort file2)

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