比较两个忽略元素顺序的XML字符串 [英] Compare two XML strings ignoring element order

问题描述

支持我有两个xml字符串

Support I have two xml strings

<test>
  <elem>a</elem>
  <elem>b</elem>
</test>

<test>
  <elem>b</elem>
  <elem>a</elem>
</test>

如何编写一个比较这两个字符串并忽略元素顺序的测试？

How to write a test that compares those two strings and ignores the element order?

我希望测试尽可能短，没有10行XML解析的地方等等。我正在寻找一个简单的断言或smt类似。

I want the test to be as short as possible, no place for 10-line XML parsing etc. I'm looking for a simple assertion or smt similar.

我有这个（不起作用）

   Diff diff = XMLUnit.compareXML(expectedString, actualString);   
   XMLAssert.assertXMLEqual("meh", diff, true);

推荐答案

我原来的答案已经过时了。如果我必须再次构建它，我将使用xmlunit 2和xmlunit-matchers。请注意，对于xml单元，不同的订单总是相似不等于。

My original answer is outdated. If I would have to build it again i would use xmlunit 2 and xmlunit-matchers. Please note that for xml unit a different order is always 'similar' not equals.

@Test
public void testXmlUnit() {
    String myControlXML = "<test><elem>a</elem><elem>b</elem></test>";
    String expected = "<test><elem>b</elem><elem>a</elem></test>";
    assertThat(myControlXML, isSimilarTo(expected).withNodeMatcher(new DefaultNodeMatcher(ElementSelectors.byNameAndText)));
    //In case you wan't to ignore whitespaces add ignoreWhitespace().normalizeWhitespace()
    assertThat(myControlXML, isSimilarTo(expected).ignoreWhitespace().normalizeWhitespace().withNodeMatcher(new DefaultNodeMatcher(ElementSelectors.byNameAndText)));
}  

如果有人仍然不想在这里使用纯Java实现。此实现从xml中提取内容并比较列表忽略顺序。

If somebody still want't to use a pure java implementation here it is. This implementation extracts the content from xml and compares the list ignoring order.

public static Document loadXMLFromString(String xml) throws Exception {
    DocumentBuilderFactory factory = DocumentBuilderFactory.newInstance();
    DocumentBuilder builder = factory.newDocumentBuilder();
    InputSource is = new InputSource(new StringReader(xml));
    return builder.parse(is);
}

@Test
public void test() throws Exception {
    Document doc = loadXMLFromString("<test>\n" +
            "  <elem>b</elem>\n" +
            "  <elem>a</elem>\n" +
            "</test>");
    XPathFactory xPathfactory = XPathFactory.newInstance();
    XPath xpath = xPathfactory.newXPath();
    XPathExpression expr = xpath.compile("//test//elem");
    NodeList all = (NodeList) expr.evaluate(doc, XPathConstants.NODESET);
    List<String> values = new ArrayList<>();
    if (all != null && all.getLength() > 0) {
        for (int i = 0; i < all.getLength(); i++) {
            values.add(all.item(i).getTextContent());
        }
    }
    Set<String> expected = new HashSet<>(Arrays.asList("a", "b"));
    assertThat("List equality without order",
            values, containsInAnyOrder(expected.toArray()));
}

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