如何从unix中的巨大文本文件中获取一些特定的行? [英] How to get some specific lines from huge text file in unix?

问题描述

我使用基于分隔文本文件的导入系统.使用的文件有时几乎有 2 Gb 大，我必须检查该文件中的一些行.所以我想知道如何输出(在另一个文件上，或者只是在屏幕上)特定值的行?例如.行号 1010123、1002451、994123 等，与源文件中的行号完全一样吗?

I use importing systems based on delimited text files. The files used can sometimes be almost 2 Gb big and I have to check some lines from that file. So I want to know how can I output (on another file, or just on screen) the lines of specific value? E.g. line number 1010123, 1002451, 994123, etc., exactly as they are in the source file?

推荐答案

要打印行 N，请使用:

sed 'Nq;d' file

打印多行(假设它们按升序排列)例如994123、1002451、1010123:

To print multiple lines (assuming they are in ascending order) e.g. 994123, 1002451, 1010123:

sed '994123p;1002451p;1010123q;d' file

最后一行号后的q告诉sed在到达第1010123行时退出，而不是通过循环我们不感兴趣的剩余行来浪费时间in.这就是为什么它对大文件很有效.

The q after the last line number tells sed to quit when it reaches the 1010123th line, instead of wasting time by looping over the remaining lines that we are not interested in. That is why it is efficient on large files.

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