Php 获取部分 url 的值 [英] Php get value of part of url

问题描述

我有一个网址(如下).我想得到2"的值.我怎样才能得到它?

I have a url (as below). I'd like to get the value of "2". How can I get that?

http://domain.com/site1/index.php/page/2

推荐答案

您正在寻找的是 pathinfo 和 parseurl:

What you're looking for is a combination of pathinfo and parseurl:

pathinfo(parseurl($url)['path'])['filename'];

pathinfo 会将路径分解为明确定义的部分，其中 filename 是您要查找的最后一部分 (2).如果您正在查找路径中的绝对位置，您可能希望在 / 上拆分路径并简单地获取索引 3 处的值.

pathinfo will break the path into well-defined parts, of which filename is that last part you're looking for (2). If you're looking instaed for the absolute location in the path, you may want to split the path on / and simply get the value at index 3.

我们可以这样测试:

<?php
$url = "http://domain.com/site1/index.php/page/2";
$value=pathinfo(parse_url($url)['path'])['filename'];
echo $value."\n";

然后在命令行上:

$ php url.php 
2

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