PHP 获取 URL 的 URI 部分 [英] PHP get URI parts of URL

问题描述

我有 2 个字符串并替换它们，所以我只得到 URI 部分.

I have 2 strings and substitute them, so I get just URI parts.

$base_url = 'http://localhost/project/';
$url      = 'http://localhost/project/controller/action/param1/param2';

我正在检查 URI 部分.

I am checking for URI parts.

$only_segments = str_replace($base_url, '', $real_url);

基本上我这样做:{url} - {base_url} = {only_segments}

然后我可以得到片段:

$parts = explode('/', $only_segments);
print_r($parts);

问题:

我是否走在正确的道路上，还是可以通过 $_SERVER['REQUEST_URI'] 更轻松地完成?

Am I on right path or can it be done easier with $_SERVER['REQUEST_URI'] ?

注意:我不想在 URI 部分使用 project，它是 localhost 的子文件夹.

Note: I don't want project in URI parts, it is sub-folder of localhost.

推荐答案

查看parse_url().这样你就可以完成大部分任务了.您需要做的就是删除作为基本 URL 一部分的路径部分.

Look into parse_url(). That will get you most of the way there. All you would need to do is remove the portion of the path that is part of your base URL.

print_r(parse_url('http://localhost/project/controller/action/param1/param2'));

Array
(
    [scheme] => http
    [host] => localhost
    [path] => /project/controller/action/param1/param2
)

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