REQUEST_URI：echo $ url：只获取url的数量 [英] REQUEST_URI: echo$url : only get the number of url

问题描述

我有一个招聘服务网站。
当人们对空缺做出回应时，空缺的网址会在回复表单（隐藏字段）中回显，以便我看到他们回复的空缺。

我在响应按钮上使用此代码，它将重定向到响应表单：

  vacature = $ url =http：//。$ _ SERVER ['HTTP_HOST']。$ _ SERVER ['REQUEST_URI']; echo $ url; 
  

在网站上，空位有标题的链接，加上空缺编号： website_url / vacancy_title-number
例如： www.test.com/director-sales-120

在响应表单中，我使用它从网址获取信息：

  echo htmlspecialchars（$ _GET ['vacature']）; 
  

对于我们购买的新crm系统，我们只需要数字，而不是网址的其余部分。我如何只从网址中获取数字？或者我怎么才能把这个号码加入到网址中;）

非常感谢！

解决方案

  $ str =www.test.com/director-sales-120; 
 $ arr = explode（ - ，$ str）; 
 echo $ arr [2]; 
  

I have a website for recruitment services. When people respond to a vacancy, the url of the vacancy is echo'd in the response form (hidden field) so I see on what vacancy they respond.

I use this code for it on the response button, it redirects to the response form:

    vacature= $ url="http://".$_SERVER['HTTP_HOST'].$_SERVER['REQUEST_URI'];echo $url;

On the website the vacancies have links of the title, combined with the vacancy number: website_url/vacancy_title-number For example: www.test.com/director-sales-120

In the response form I use this to get the info out of the url:

    echo htmlspecialchars ($_GET['vacature']);

For the new crm system we bought, we need only the number, not the rest of the url. How do I get only the number out of the url? Or how do I only get the number into the url ;)

Thanks a lot in advance!

解决方案

$str = "www.test.com/director-sales-120";
$arr=explode("-",$str);
echo $arr[2];

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