结合重复＆QUOT;嵌套＆QUOT;阵列的Javascript（使用每周打开和关闭的时间） [英] Combining Duplicate "Nested" Arrays Javascript (Using for weekly open and closed hours)

问题描述

这一个是我的烘焙面大的时候！

我有一个数组，看起来像这样里面的一些阵列

  VAR lidHours = {192611：[
[07:00，21:30]，
[07:00，21:30]，
[07:00，21:30]，
[09:00，21:30]，
[09:00，00:00]
[08:00，08:00]，
[，]
]
}
 

和的工作日数组

  VAR平日=新的Array（星期一，星期二，星期三，星期四，星期五，星期六，太阳）;
 

因此​​，每个阵列重新presents一周中的一天。我到输出这样的页面：周一：07：00 - 21:00等等...

但你可以看到，第3天有相同的时间，我的目标是把它显示是这样的：

 周一至周三：7：00  -  9:00
周四：9:00  -  9:30
周五：9：00  -  12:00
星期六：8:00  -  8:00
孙：关闭
 

我可以格式化小时，知道他们什么时候关闭，军事转换为标准，但我不能弄清楚如何重复小时（周一至周三）结合起来，我怎么能preserve星期一，知道了最后重复一天周三??

任何帮助将是如此之大的AP preciated。谢谢！

解决方案

  VAR combined_hours = [];
VAR openHours = lidHours [192611];
VAR prevHours;
对于（VAR天= 0;日间及LT; openHours.length;天++）{
    VAR curHours = openHours [日]
    如果（curHours [0]！= prevHours [0] || curHours [1]！= prevHours [1]）{
        combined_hours.push（{朝九特派：平日[日]
                              endday指定：，
                              开放：curHours [0]
                              收盘：curHours [1]}）;
        prevHours = curHours;
    }其他{
        combined_hours [combined_hours.length-1] .endDay =' - '+平日[日]
    }
}
 

现在可以显示combined_hours。

This one is baking my noodle big time!

I have some arrays inside an array that looks like this

var lidHours = {"192611":[
["07:00","21:30"],
["07:00","21:30"],
["07:00","21:30"],
["09:00","21:30"],
["09:00","00:00"],
["08:00","08:00"],
["",""]
]
}

And an array of the week days

var weekDays = new Array("Mon", "Tue", "Wed", "Thur", "Fri", "Sat", "Sun");

So each array represents a day of the week. I'm outputting onto the page like this: Monday: 7:00 - 21:00 and so on...

But you can see that the first 3 days have the exact same hours, my goal is to have it display like this:

Mon-Wed: 7:00 - 9:00
Thu: 9:00 - 9:30
Fri: 9:00 - 12:00
Sat: 8:00 - 8:00
Sun: Closed

I can format the hours and know when they are closed and convert from military to standard, but I cant figure out how to combine the duplicate hours(Mon-Wed) and how can I preserve Mon and know that the last duplicate day was Wed??

Any help would be so greatly appreciated. Thanks!

解决方案

var combined_hours = [];
var openHours = lidHours["192611"];
var prevHours;
for (var day = 0; day < openHours.length; day++) {
    var curHours = openHours[day];
    if (curHours[0] != prevHours[0] || curHours[1] != prevHours[1]) {
        combined_hours.push({ startDay: weekDays[day],
                              endDay: "", 
                              open: curHours[0], 
                              close: curHours[1] });
        prevHours = curHours;
    } else {
        combined_hours[combined_hours.length-1].endDay = '-' + weekdays[day];
    }
}

Now you can display combined_hours.

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