使用beautifulsoup在div中获取孩子的文本 [英] Get text of children in a div with beautifulsoup

问题描述

您好，我想了解 Google Play 商店中某个应用的说明.(https://play.google.com/store/apps/details?id=com.wetter.androidclient&hl=de)

导入 urllib2从 bs4 导入 BeautifulSoup汤 = BeautifulSoup(urllib2.urlopen("https://play.google.com/store/apps/details?id=com.wetter.androidclient&hl=de"))result = soup.find_all("div", {"class":"show-more-content text-body"})

通过此代码，我获得了该课程的全部内容.但我不能只得到其中的文字.我用 next_silbing 或 .text 尝试了很多东西，但它总是抛出错误(ResultSet 没有属性 xxx).

我只想得到这样的文字:Die Android App von wetter.com！Sie erhalten:..:"

有人可以帮我吗?

解决方案

在元素上使用 .text 属性；你有一个list结果，所以循环:

 for res in result:打印资源文本

或者，如果只有一个这样的

，使用.find()而不是>.find_all():

result = soup.find("div", {"class":"show-more-content text-body"})打印结果.text

Hi i want the description of an App in the Google Playstore. (https://play.google.com/store/apps/details?id=com.wetter.androidclient&hl=de)

import urllib2
from bs4 import BeautifulSoup

soup = BeautifulSoup(urllib2.urlopen("https://play.google.com/store/apps/details?id=com.wetter.androidclient&hl=de"))
result = soup.find_all("div", {"class":"show-more-content text-body"})

With this code i get the whole content in this class. But i can't get only the text in it. I tried a lot of things with next_silbing or .text but it always throws errors(ResultSet has no attribute xxx).

I just want to get the text like this: "Die Android App von wetter.com! Sie erhalten: ..:"

Anyone can help me?

解决方案

Use the .text attribute on the elements; you have a list of results, so loop:

for res in result:
    print res.text

Alternatively, if there is only ever supposed to be one such <div>, use .find() instead of .find_all():

result = soup.find("div", {"class":"show-more-content text-body"})
print result.text

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