使用 BeautifulSoup，如何仅从特定选择器中获取文本而没有孩子中的文本? [英] Using BeautifulSoup, how to get text only from the specific selector without the text in the children?

问题描述

我不知道如何编码 BeautifulSoup 以便它只给我来自所选标签的文本.我得到了更多诸如它的孩子(们)的文字！

I don't know how to code BeautifulSoup so that it gives me only the text from the selected tag. I get more such as the text of its child(ren)!

例如:

from bs4 import BeautifulSoup
soup = BeautifulSoup('<div id="left"><ul><li>"I want this text"<a href="someurl.com"> I don\'t want this text</a><p>I don\'t want this either</li><li>"Good"<a href="someurl.com"> Not Good</a><p> Not Good either</li></ul></div>', "html5lib") 
x = soup.select('ul > li')
for i in x:
    print(i.text)

输出:

我想要这个文本"我不要这个文字我也不要这个

"I want this text" I don't want this textI don't want this either

好"不好也不好

期望的输出:

我想要这个文本"

好"

推荐答案

一个选择是获取 contents 列表:

One option would be to get the first element of the contents list:

for i in x:
    print(i.contents[0])

另一个 - 找到第一个文本节点:

Another - find the first text node:

for i in x:
    print(i.find(text=True))

两者都会打印:

"I want this text"
"Good"

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