如何复制阵列的部分到另一个数组 [英] How to copy portions of an array into another array

问题描述

早上好！我需要一个阵列的一部分复制到另一个阵列开始在位置2和消费所有的剩余价值。第一个数组是类型'的argv数组的char **，但第二个数组必须是类型为const char *'的。看来，有两种方法在C ++中这样做 - STD：复制和memcpy。这将是更好地处理这种情况，因为这两个数组是不同类型的，哪些会为例会是什么样子？

Good morning! I need to copy a portion of one array into another array starting at position 2 and consuming all the remaining value. The first array is the 'argv' array of type 'char**' but the second array needs to be of type 'const char*'. It appears that there are two ways to do this in C++ - std:copy and memcpy. Which would be better to handle this situation since the two arrays are of different types and what would an example look like?

推荐答案

有在C ++使用的memcpy（）很少有很好的理由。如果我理解你的要求正确地，这里有一个如何使用做一个例子的std ::复制（）。

There's very few good reasons to use memcpy() in C++. If I understand what you're asking correctly, here's an example of how to do it using std::copy().

vector<char*> args(argc - 2);
copy(argv + 2, argv + argc, begin(args));

活生生的例子。

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