在Java中的数组查找的平均 [英] Finding the average in an array in Java

问题描述

我必须找到在一个数组是从一个特定的号码（例如不同的元件的平均值：{2,6,4,7,7,4,2,5}是阵列如何找到平均从4个不同的元素？）

解决方案

 进口java.util.Scanner中;公共类ArrAvg {公共静态无效的主要（字串[] args）{    诠释一个[] = {1,2,3,4,5,6,7,8,9,10};
    INT发生= 0;
    双总和= 0;
    双平均= 0;    的for（int i = 0; I＆LT;则为a.length;我++）{        如果（一个由[i] == 4）{
            发生++;
        }
    }
    的for（int i = 0; I＆LT;则为a.length;我++）{        如果（一个由[i]！= 4）{
            总和=总和+ A [];
        }
    }
    的System.out.println（平均=总和/（则为a.length-发生））;    }}
 

I have to find the average value of the elements in an array that are different from a specific number (example: {2,6,4,7,7,4,2,5} is the array. How to find the average of the elements different from 4?)

解决方案

import java.util.Scanner;

public class ArrAvg {

public static void main(String[] args) {

    int a[] = {1,2,3,4,5,6,7,8,9,10};
    int occur = 0;
    double sum = 0;
    double avg = 0;

    for (int i = 0; i < a.length; i++) {

        if (a[i] == 4) {
            occur++;
        }
    }
    for (int i = 0; i < a.length; i++) {

        if (a[i] != 4) {
            sum =  sum + a[i];
        }
    }
    System.out.println(avg = sum / (a.length-occur));

    }

}

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