查找数组的算术平均值:C# [英] Finding the Arithmetic Mean of an Array: C#

问题描述

语言:C#

我有一个用户输入的数字数组，我想找到该数组的算术平均值.

I have an array of numbers that the user entered, and I want to find the arithmetic mean of the array.

我查看了两个类似的案例，但是找不到真正想要的东西...无论如何，这是代码:

I looked up a couple of similiar cases, but couldn't really find anything I was looking for... Anyway, here is the code:

            Console.WriteLine("\n How many numbers do you want to average? \n");

            int nNumtoAvg = Convert.ToInt32(Console.ReadLine());


            int[] nListToAverage = new int[nNumtoAvg];



            for (int i = 0; i < nNumtoAvg; i++)
            {

                Console.WriteLine("Enter whole number #" + (i + 1) + ": ");

                string sVal = Console.ReadLine();

                int nValue = Convert.ToInt32(sVal);

                nListToAverage[i] = nValue;

            }

现在，我该怎么做才能将数组中的所有数字加在一起，然后将其除以array.Length?在此先感谢:D

Now, what would I do to add all the numbers in the array together, and then divide that by the array.Length? Thanks in advance :D

推荐答案

如果需要将int作为结果，怎么做:

If you need an int as the result, how about:

int average = Convert.ToInt32(nListToAverage.Average());

否则，您会得到更精确的答案:

Otherwise, you get a more precise answer with a double:

double average = nListToAverage.Average();

如果需要先添加所有项目，则还可以执行以下操作:

If you need to add all the items first, you can also do:

int average = nListToAverage.Sum() / nListToAverage.Length;

或者用老式的工作方式:

Or the old-school, show-your-work way:

int sum = 0;
int average = 0;
int numItems = nListToAverage.Length;

if (numItems > 0)
{
    for(int i = 0; i < numItems; i++)
    {
        sum += nListToAverage[i];
    }

    average = sum / numItems;
}

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