在 VB 6 的 Shell 命令中传递参数 [英] Passing parameters in Shell command in VB 6

问题描述

我在 VB 6 中有 2 个 EXE.EXE 1 通过 shell 命令调用另一个 EXE2

I have 2 EXEs in VB 6. EXE 1 calls the other EXE2 through shell command

EXE1:Shell(路径名\EXE2,0)

EXE1 : Shell(PathName\EXE2,0)

现在我只想将一个字符串类型变量传递给我希望在该 EXE2 中接收的 EXE2.我怎样才能达到同样的目标?

Now all I want is to pass a string type variable to EXE2 which I wish to receive in that EXE2. How can I achieve the same?

提前致谢

推荐答案

只需将字符串(可能带引号)附加到文件名的末尾:

Simply append the string (possibly quoted) to the end of the filename:

Shell("""PathName.exe"" wibble", vbNormalFocus)

或:

Shell("""PathName.exe"" ""wibble"" ""wibble 2""", vbNormalFocus)

然后可以使用 Command$() 函数在其他应用程序中读取此值，该函数将包含路径名和空格之后的所有内容，包括参数周围的任何引号(例如 "wibble" "wibble 2").

This value can then be read in the other application using the Command$() function which will include everything after the path name and space, including any quotes around the parameters (e.g. "wibble" "wibble 2").

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