如何获得日期的天数 [英] How to get the days for the date

问题描述

第 1 部分

Dim totdays as long
totdays = DateDiff("d", "01/2011", DateAdd("m", 1, "01/2011"))

上面的代码会返回31"

The above code will return "31"

我想得到那个 31 的日子

I want to get the days for that 31

预期输出

Monday (31/01/2011)

需要 VB6 代码帮助

Need VB6 Code Help

第 2 部分

我想找到特定月份的星期日....

I want to find the sundays on the particular month....

例如，如果我选择 01/2012 月份，查询应该给出这样的结果

For Example, If i select the month 01/2012, The query should give the result like this

01
08
15
22
29

以上日期为星期日.

01/2012 月的预期输出

01
08
15
22
29

推荐答案

something like this (tested in vba)

something like this (tested in vba)

周日子查询的最终更新

根据下面 Gopal 评论中的要求

As per request in commentd from Gopal below

    Dim strDate As String
    Dim dtStart As Date
    Dim dtEnd As Date
    Dim stEnd As Date
    Dim lngCnt As Long
    Dim strOut As String
    strDate = "01/2012"
    dtStart = DateValue(strDate)
    dtEnd = DateAdd("d", DateDiff("d", strDate, DateAdd("m", 1, strDate) - 1), dtStart)
    lngCnt = Weekday(dtStart) - 7
    Do
        lngCnt = lngCnt + 7
        strOut = strOut & Format(lngCnt, "00") & vbNewLine
    Loop While lngCnt + 7 <= dtEnd - dtStart
    MsgBox strOut

更新

请注意，我需要使用 lngdays-1 来添加不到一个月的 1 天(即 31-Jan-2011)，否则结果将是 01-Feb-2011

Note that I needed to use lngdays-1 to add 1 day less than a month (ie 31-Jan-2011), else you would have had 01-Feb-2011 as the result

Dim strDate As String
Dim lngdays As Long
strDate = "01/2011"
lngdays = DateDiff("d", strDate, DateAdd("m", 1, strDate))
MsgBox Format(DateAdd("d", lngdays - 1, strDate), "dddd (dd/mm/yyyy)")

旧

 Dim lngdays As Long
 lngdays = DateDiff("d", "01/2011", DateAdd("m", 1, "01/2011"))
 MsgBox Format(DateSerial(2011, 1, lngdays), "dddd (dd/mm/yyyy)")

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