如何获取日期的天数 [英] How to get the days for the date
本文介绍了如何获取日期的天数的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
Part 1
Dim totdays as long
totdays = DateDiff("d", "01/2011", DateAdd("m", 1, "01/2011"))
The above code will return "31"
I want to get the days for that 31
Expected Output
Monday (31/01/2011)
Need VB6 Code Help
Part 2
I want to find the sundays on the particular month....
For Example, If i select the month 01/2012, The query should give the result like this
01
08
15
22
29
The above dates are sunday.
Expected Output for 01/2012
Month
01
08
15
22
29
解决方案
something like this (tested in vba)
final update for the Sunday sub-query
As per request in commentd from Gopal below
Dim strDate As String
Dim dtStart As Date
Dim dtEnd As Date
Dim stEnd As Date
Dim lngCnt As Long
Dim strOut As String
strDate = "01/2012"
dtStart = DateValue(strDate)
dtEnd = DateAdd("d", DateDiff("d", strDate, DateAdd("m", 1, strDate) - 1), dtStart)
lngCnt = Weekday(dtStart) - 7
Do
lngCnt = lngCnt + 7
strOut = strOut & Format(lngCnt, "00") & vbNewLine
Loop While lngCnt + 7 <= dtEnd - dtStart
MsgBox strOut
updated
Note that I needed to use lngdays-1
to add 1 day less than a month (ie 31-Jan-2011), else you would have had 01-Feb-2011 as the result
Dim strDate As String
Dim lngdays As Long
strDate = "01/2011"
lngdays = DateDiff("d", strDate, DateAdd("m", 1, strDate))
MsgBox Format(DateAdd("d", lngdays - 1, strDate), "dddd (dd/mm/yyyy)")
old
Dim lngdays As Long
lngdays = DateDiff("d", "01/2011", DateAdd("m", 1, "01/2011"))
MsgBox Format(DateSerial(2011, 1, lngdays), "dddd (dd/mm/yyyy)")
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