将 NA 重新插入向量 [英] Re-inserting NAs into a vector

问题描述

我有一个包含 NA 的值向量.这些值需要由无法处理 NAs 的外部程序处理，因此它们被剥离，写入文件，处理，然后读回，从而产生一个长度为非 NAs 数量的向量.例如，假设输入是 7 3 4 NA 5 4 6 NA 1 NA，那么输出就是 7 个值.我需要做的是将 NA 重新插入到位.

I have a vector of values which include NAs. The values need to be processed by an external program that can't handle NAs, so they are stripped out, its written to a file, processed, then read back in, resulting in a vector of the length of the number of non-NAs. Example, suppose the input is 7 3 4 NA 5 4 6 NA 1 NA, then the output would just be 7 values. What I need to do is re-insert the NAs in position.

所以，给定两个向量 X 和 Y:

So, given two vectors X and Y:

 > X
 [1]  64   1   9 100  16  NA  25  NA   4  49  36  NA  81
 > Y
 [1]  8  1  3 10  4  5  2  7  6  9

生产:

8 1 3 10 4 NA 5 NA 2 7 6 NA 9

(你可能注意到 X 是 Y^2，这只是一个例子).

(you may notice that X is Y^2, thats just for an example).

我可以敲出一个函数来做到这一点，但我想知道是否有任何巧妙的方法可以做到这一点......拆分，列表，长度......嗯......

I could knock out a function to do this but I wonder if there's any nice tricksy ways of doing it... split, list, length... hmmm...

推荐答案

同一主题的另一个变体

rena <- function(X,Z){
    X[which(!is.na(X))]=Z    
    X
}

R 自动用 NA 填充其余部分.

R automatically fills the rest with NA.

Marek 更正.

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