在vim中查找完全匹配 [英] Finding exact match in vim

问题描述

使用 / 或 ? 可以在 vim 中找到一个单词的匹配项.但是我怎样才能找到一个完全匹配的呢?例如，我的文本包含以下单词: a aa aaa aaaa aa 并且我输入 /aa 这将找到包含模式 aa 的所有字符串，但是如果我想要怎么办准确地找到 aa 而不是 aaaa aaaa?

Using / or ? enables to find a match for a word in vim. But how can I find an exact match? For example, my text contains the following words: a aa aaa aaaa aa and I type /aa This will find all the strings containing the pattern aa, but what if I want to find exactly aa and not aaaa aaaa?

推荐答案

找到一个独立的 aa(不是 a, aaa, ...)，您需要在前后都断言该字符不匹配.这是通过负lookbehind(在Vim的正则表达式语法中为\@)和lookahead(\@!code>) 封闭匹配本身 (a\{2}):

To find a single, standalone aa (not a, aaa, ...), you need to assert no match of that character both before and afterwards. This is done with negative lookbehind (\@<! in Vim's regular expression syntax) and lookahead (\@!) enclosing the match itself (a\{2}):

/\%(a\)\@<!a\{2}\%(a\)\@!/

简化

那些断言很难输入，如果匹配周围的边框也是非关键字/关键字边框，你可以使用较短的\<\a\{2}\> 断言(如在 MosteM 的回答中)，但这在一般情况下不起作用，例如使用 xaax.

Simplification

Those assertions are hard to type, if the border around the match is also a non-keyword / keyword border, you can use the shorter \<\a\{2}\> assertions (as in MosteM's answer), but this doesn't work in the general case, e.g. with xaax.

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