关于结构的警告 C26495? [英] Warning C26495 on structures?

问题描述

过去一两年我一直在使用 C#/.NET，但我正在为客户端更新旧的 C++/MFC 应用程序.我知道自从我上次使用 C++ 以来已经发生了很多变化，但这种变化让我很失望.

I've been using C#/.NET for the past decade or two, but am updating an old C++/MFC application for a client. I know a lot has changed since I last worked with C++, but this one kind of threw me.

我有以下结构:

typedef struct _FILTERINFO {
    int nCustomerID;
    CString sCustomerName;
} FILTERINFO, *LPFILTERINFO;

Visual Studio 2019 给了我一个警告:

And Visual Studio 2019 gives me a warning:

警告 C26495 变量_FILTERINFO::nCustomerID"未初始化.总是初始化一个成员变量(type.6).

Warning C26495 Variable '_FILTERINFO::nCustomerID' is uninitialized. Always initialize a member variable (type.6).

那么，这里有什么问题，我将如何初始化变量?如您所见，我没有构造函数.我现在不需要它们用于结构，是吗?

So, what is the problem here and how would I initialize the variable? As you can see, I don't have a constructor. I don't need them for structures now do I?

注意:进一步研究这一点，我看到我的应用定义了其他 struct，但由于某种原因没有收到同样的警告.它似乎特定于大约两个或三个声明.

NOTE: Looking into this further, I see my app defines other struct that for some reason do not get this same warning. It seems specific to about two or three declarations.

推荐答案

去掉 typedef，你在做 C++，所以改写:

Drop the typedef, you are doing C++, so instead write:

struct FILTERINFO 
{ 
  int nCustomerID=0; 
  CString sCustomerName; 
};

和

typedef FILTERINFO* LPFILTERINFO; 

通常最好不要对指针进行 typedef，而是使用 FILTERINFO* 因为有时与 const

Normally it is better to not do a typedef of a pointer, use instead FILTERINFO* because sometimes you get unexpected behavior when used with const

这篇关于关于结构的警告 C26495?的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！