获取用户的IP地址 [英] Get User's IP Address

问题描述

我怎样才能得到当前访问者的IP地址？

How can I get the current visitors IP address?

推荐答案

编辑：也发现了关于IP相关的HTTP头一个有趣的问题<一href=\"http://stackoverflow.com/questions/527638/getting-the-client-ip-address-remote-addr-http-x-forwarded-for-what-else-could\">here.

also found an interesting question regarding IP-related http headers here.

EDIT2：正如在评论中提到，并在链接我上面提供的 HTTP_X_FORWARDED_FOR 头可以包含由逗号分隔的多个IP-地址。我没遇到过这种情况，但假设需要一些更正我的回答。

As mentioned in comments and in link I provided above, HTTP_X_FORWARDED_FOR header may contain multiple IP-addresses separated by comma. I didn't face this situation but suppose some corrections to my answer are required.

我用这个code来获得IP地址（如果得到某种原因失败则返回 IPAddress.None 值）：

I use this code to get the IP address (it returns IPAddress.None value if getting failed for some reason):

    /// <summary>
    /// Gets the IP address of the request.
    /// <remarks>
    /// This method is more useful than built in because in some cases it may show real user IP address even under proxy.
    /// <summary>
    /// Gets the IP address of the request.
    /// <remarks>
    /// This method is more useful than built in because in some cases it may show real user IP address even under proxy.
    /// The <see cref="System.Net.IPAddress.None" /> value will be returned if getting is failed.
    /// </remarks>
    /// </summary>
    /// <param name="request">The HTTP request object.</param>
    /// <returns></returns>
    public static IPAddress GetIp(this HttpRequest request)
    {
        string ipString;
        if (string.IsNullOrEmpty(request.ServerVariables["HTTP_X_FORWARDED_FOR"]))
        {
            ipString = request.ServerVariables["REMOTE_ADDR"];
        }
        else
        {
            ipString = request.ServerVariables["HTTP_X_FORWARDED_FOR"].Split(",".ToCharArray(), StringSplitOptions.RemoveEmptyEntries)
                .FirstOrDefault();
        }

        IPAddress result;
        if (!IPAddress.TryParse(ipString, out result))
        {
            result = IPAddress.None;
        }

        return result;
    }

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