WCF XML 结构 - 如何删除包装节点? [英] WCF XML structure - how to remove wrapper nodes?

问题描述

我在使用 List 对象时遇到问题:

I am having trouble when using List objects:

[DataContract]
public class Recipe
{
        [DataMember(Name="Allergies")]
        public List<AllergyModel> Allergies { get; set; }
}

[DataContract]    
public class AllergyModel
{
    public string Allergy { get; set; }
}

如何使生成的 XML 不包含 AllergyModel 节点?当我读取 Recipe 参数时，Allergies 列表属性为 null，因为在原始 XML 结构中没有 AllergyModel 节点.

How do I make the XML produced not include the AllergyModel node? When I come to read the Recipe parameter, the Allergies list property is null because in the original XML the structure does not have the AllergyModel node.

<Allergies>
    <a:AllergyModel>
        <a:Allergy>nuts</a:Allergy>
    </a:AllergyModel>
    <a:AllergyModel>
        <a:Allergy>wheat</a:Allergy>
    </a:AllergyModel>
</Allergies>

推荐答案

尝试改用自定义集合:

[CollectionDataContract(Name = "Allergies", ItemName = "Allergy")]
public class AllergyList : List<string>
{
    ...
}

使用此集合代替 List.重要的是，您可以在自定义集合中传递项目的名称.

Use this collection instead of List<AllergyModel>. The important is that you can pass the name of the item in the custom collection.

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