包装一组 XML 节点 [英] Wrap group of XML nodes

问题描述

我正在使用 PHP5，我需要按以下形式转换 XML:

Im working with PHP5, and I need to transform XML in the following form:

<list>
    <item label="(1)">some text</item>
    <item label="(2)">
        <anotherNode>some text</anotherNode
        <item label="a">some text</item>
        <item label="b">some text</item>          
    </item>
</list>

变成这样:

<list>
    <item label="(1)">some text</item>
    <item label="(2)">
        <anotherNode>some text</anotherNode>
        <list> <!-- opening new wrapper node-->
            <item label="a">some text</item>
            <item label="b">some text</item>
        </list> <!-- closing new wrapper node-->
    </item>
</list> 

正如您在上面看到的，我需要向任何尚未被列表"节点包装的项目"节点添加一个包装节点.

As you can see above I need to add a wrapper node to any 'item' nodes that are not wrapped by the 'list' node already.

将源 xml 转换为目标 xml 有哪些可能的解决方案?

What are possible solutions for transforming source xml to the target xml?

更新:

注意 1:任何单个或一组 节点都需要用 节点包装，如果它尚未包装.

Note 1: Any single or group of <item> nodes needs to be wrapped by a <list> node if its not wrapped already.

注意 2:需要保持内容的顺序.

Note 2: Order of the content needs to be maintained.

注3:如果在前后有节点.它应该改变这个:

Note 3: If there are <item> nodes before and after <anotherNode>. It should transform this:

<list>
    <item label="(1)">some text</item>
    <item label="(2)">
        <item label="a">some text</item>
        <item label="b">some text</item>          
        <anotherNode>some text</anotherNode>
        <item label="c">some text</item>
        <item label="d">some text</item>          
    </item>
</list>

进入这个:

<list>
    <item label="(1)">some text</item>
    <item label="(2)">
        <list> <!-- opening new wrapper node-->
            <item label="a">some text</item>
            <item label="b">some text</item>          
        </list> <!-- closing new wrapper node-->
        <anotherNode>some text</anotherNode>
        <list> <!-- opening new wrapper node-->
            <item label="c">some text</item>
            <item label="d">some text</item>
        </list> <!-- closing new wrapper node-->
    </item>
</list>

谢谢，

推荐答案

这种转变:

<xsl:stylesheet version="1.0"
 xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
 <xsl:output omit-xml-declaration="yes" indent="yes"/>
 <xsl:strip-space elements="*"/>

 <xsl:template match="node()|@*" name="identity">
  <xsl:copy>
   <xsl:apply-templates select="node()|@*"/>
  </xsl:copy>
 </xsl:template>

 <xsl:template match="item/item[1]">
  <list>
   <xsl:apply-templates mode="copy"
    select=".| following-sibling::item"/>
  </list>
 </xsl:template>

 <xsl:template match="item" mode="copy">
  <xsl:call-template name="identity"/>
 </xsl:template>

 <xsl:template match="item/item[not(position()=1)]"/>
</xsl:stylesheet>

应用于提供的 XML 文档时:

<list>
    <item label="(1)">some text</item>
    <item label="(2)">
        <anotherNode>some text</anotherNode>
        <item label="a">some text</item>
        <item label="b">some text</item>
    </item>
</list>

产生想要的、正确的结果:

<list>
   <item label="(1)">some text</item>
   <item label="(2)">
      <anotherNode>some text</anotherNode>
      <list>
         <item label="a">some text</item>
         <item label="b">some text</item>
      </list>
   </item>
</list>

请注意:

1. 身份规则的使用和覆盖.

抑制某些元素.

使用不同的模式处理某些元素.

The processing of certain elements using a different mode.

更新:

OP 增加了额外的要求:

The OP has added additional requirements:

"如果在 anothernode 之前和之后有 item 元素，那么每个这样的 item 元素组必须被包围在一个单独的list"

"In case there are item elements before anothernode and after it, then each such group of item elements must be enclosed in a separate list"

<xsl:stylesheet version="1.0"
 xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
 <xsl:output omit-xml-declaration="yes" indent="yes"/>
 <xsl:strip-space elements="*"/>

 <xsl:key name="kfollnonitem" match="item"
  use="generate-id(preceding-sibling::*[not(self::item)][1])"/>

 <xsl:key name="kprecnonitem" match="item"
  use="generate-id(following-sibling::*[not(self::item)][1])"/>

 <xsl:template match="node()|@*" name="identity">
  <xsl:copy>
   <xsl:apply-templates select="node()|@*"/>
  </xsl:copy>
 </xsl:template>

 <xsl:template match="*[not(self::list)]/item[1]">
  <list>
   <xsl:apply-templates mode="copy"
    select="key('kprecnonitem',
                 generate-id(following-sibling::*[not(self::item)][1])
                 )"/>
  </list>
 </xsl:template>

 <xsl:template match=
  "*[not(self::list) and item]/*[not(self::item)]">
  <xsl:call-template name="identity"/>

  <list>
    <xsl:apply-templates mode="copy"
     select="key('kfollnonitem', generate-id())"/>
  </list>
 </xsl:template>

 <xsl:template match="item" mode="copy">
  <xsl:call-template name="identity"/>
 </xsl:template>

 <xsl:template match="item/item[not(position()=1)]"/>
</xsl:stylesheet>

当对以下 XML 文档执行此转换时:

<list>
    <item label="(1)">some text</item>
    <item label="(2)">
        <item label="a">some text</item>
        <item label="b">some text</item>
        <anotherNode>some text</anotherNode>
        <item label="c">some text</item>
        <item label="d">some text</item>
    </item>
</list>

产生想要的、正确的结果:

<list>
   <item label="(1)">some text</item>
   <item label="(2)">
      <list>
         <item label="a">some text</item>
         <item label="b">some text</item>
      </list>
      <anotherNode>some text</anotherNode>
      <list>
         <item label="c">some text</item>
         <item label="d">some text</item>
      </list>
   </item>
</list>

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