使用 Django 从服务器获取多个图像 [英] Fetch multiple images from the server using Django

问题描述

我正在尝试从服务器下载多个图像文件.我在后端使用 Django.与单张图片相关的问题已经回答，我尝试了代码，它适用于单张图片.在我的应用程序中，我想在单个 HTTP 连接中下载多个图像.

I am trying to download multiple image files from the server. I am using Django for my backend. Question related to single image has already been answered and I tried the code and it works on single image. In my application, I want to download multiple images in a single HTTP connection.

from PIL import Image

img = Image.open('test.jpg')
img2 = Image.open('test2.png')

response = HttpResponse(content_type = 'image/jpeg')
response2 = HttpResponse(content_type = 'image/png')

img.save(response, 'JPEG')
img2.save(response2, 'PNG')

return response #SINGLE

如何同时获取 img 和 img2.我想的一种方法是压缩两个图像并根据客户端大小解压缩它，但我认为这不是一个好的解决方案.有没有办法解决这个问题?

How can I fetch both img and img2 at once. One way I was thinking is to zip both images and unzip it on client size but I dont think that is good solution. Is there a way to handle this?

推荐答案

我环顾四周，找到了使用磁盘上的临时 Zip 文件的旧解决方案:https://djangosnippets.org/snippets/365/

I looked around and find an older solution using a temporary Zip file on disk: https://djangosnippets.org/snippets/365/

它需要一些更新，这应该可以工作(在 django 2.0 上测试)

It needed some updating, and this should work (tested on django 2.0)

import tempfile, zipfile
from django.http import HttpResponse
from wsgiref.util import FileWrapper

def send_zipfile(request):
    """                                                                         
    Create a ZIP file on disk and transmit it in chunks of 8KB,                 
    without loading the whole file into memory. A similar approach can          
    be used for large dynamic PDF files.                                        
    """
    temp = tempfile.TemporaryFile()
    archive = zipfile.ZipFile(temp, 'w', zipfile.ZIP_DEFLATED)
    for index in range(10):
        filename = 'C:/Users/alex1/Desktop/temp.png' # Replace by your files here.  

        archive.write(filename, 'file%d.png' % index) # 'file%d.png' will be the
                                                      # name of the file in the
                                                      # zip
    archive.close()

    temp.seek(0)
    wrapper = FileWrapper(temp)

    response = HttpResponse(wrapper, content_type='application/zip')
    response['Content-Disposition'] = 'attachment; filename=test.zip'

    return response

现在，这需要我的 .png 并在我的 .zip 中写入 10 次，然后发送.

Right now, this takes my .png and writes it 10 times in my .zip, then sends it.

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